The basic task is simple: given N real numbers,you are supposed to calculate their average. But what makes it complicated is that some of the input numbers might not be legal. A legal input is a real number in [−] and is accurate up to no more than 2 decimal places. When you calculate the average,those illegal numbers must not be counted in.
input Specification:Each input file contains one test case. For each case,the first line gives a positive integer N (≤). Then N numbers are given in the next line,separated by one space.
Output Specification:For each illegal input number,print in a line ERROR: X is not a legal number
where X
is the input. Then finally print in a line the result: The average of K numbers is Y
where K
is the number of legal inputs and Y
is their average,accurate to 2 decimal places. In case the average cannot be calculated,output Undefined
instead of Y
. In case K
is only 1,output The average of 1 number is Y
instead.
75 -3.2 aaa 9999 2.3.4 7.123 2.35Sample Output 1:
ERROR: aaa is not a legal numberERROR: 9999 is not a legal numberERROR: 2.3.4 is not a legal numberERROR: 7.123 is not a legal numberThe average of 3 numbers is 1.38Sample input 2:
2aaa -9999Sample Output 2:
ERROR: aaa is not a legal numberERROR: -9999 is not a legal numberThe average of 0 numbers is Undefined
#include<bits/stdc++.h>using namespace std;typedef long long ll;int main(){ int n,cnt = 0; cin >> n; char a[50],b[50]; double temp,sum = 0.0; for(int i=0;i < n;i++){ scanf("%s",a); sscanf(a,"%lf",&temp); //格式和scanf差不多,从a输入到temp temp加& sprintf(b,"%.2f",temp); //从temp输出到b int flag = 0; for(int j=0;j < strlen(a);j++)if(a[j]!=b[j])flag = 1; if(flag||temp < -1000||temp > 1000){ printf("ERROR: %s is not a legal number\n",a); continue; } else{ sum += temp; cnt++; } } if(cnt == 1)printf("The average of 1 number is %.2f",sum); else if(cnt > 1)printf("The average of %d numbers is %.2f",cnt,sum / cnt); else printf("The average of 0 numbers is Undefined"); return 0;}
sscanf 和 sprintf!!学到了
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