用C语言编写个五子棋的棋盘？

1.先独立完成数据结构，最简单的办法就用一个二维数组表来模拟五子棋的棋盘2.用MFC做界面，或者是用OPENCV（个人推荐这个，这个比MFC简单)里面对于做界面有一些函数，必然绘制直线，绘制圆，绘制矩形~不过得先配置OPENCV的文件~3.综合测试

#include <stdio.h>

#include <bios.h>

#include <ctype.h>

#include <conio.h>

#include <dos.h>

#define CROSSRU 0xbf /*右上角点*/

#define CROSSLU 0xda /*左上角点*/

#define CROSSLD 0xc0 /*左下角点*/

#define CROSSRD 0xd9 /*右下角点*/

#define CROSSL 0xc3 /*左边*/

#define CROSSR 0xb4 /*右边*/

#define CROSSU 0xc2 /*上边*/

#define CROSSD 0xc1 /*下边*/

#define CROSS 0xc5 /*十字交叉点*/

/*定义棋盘左上角点在屏幕上的位置*/

#define MAPXOFT 5

#define MAPYOFT 2

/*定义1号玩家的 *** 作键键码*/

#define PLAY1UP 0x1157/*上移--'W'*/

#define PLAY1DOWN 0x1f53/*下移--'S'*/

#define PLAY1LEFT 0x1e41/*左移--'A'*/

#define PLAY1RIGHT 0x2044/*右移--'D'*/

#define PLAY1DO 0x3920/*落子--空格键*/

/*定义2号玩家的 *** 作键键码*/

#define PLAY2UP 0x4800/*上移--方向键up*/

#define PLAY2DOWN 0x5000/*下移--方向键down*/

#define PLAY2LEFT 0x4b00/*左移--方向键left*/

#define PLAY2RIGHT 0x4d00/*右移--方向键right*/

#define PLAY2DO 0x1c0d/*落子--回车键Enter*/

/*若想在游戏中途退出, 可按 Esc 键*/

#define ESCAPE 0x011b

/*定义棋盘上交叉点的状态, 即该点有无棋子 */

/*若有棋子, 还应能指出是哪个玩家的棋子 */

#define CHESSNULL 0 /*没有棋子*/

#define CHESS1 'O'/*一号玩家的棋子*/

#define CHESS2 'X'/*二号玩家的棋子*/

/*定义按键类别*/

#define KEYEX99v 0/*退出键*/

#define KEYFALLCHESS 1/*落子键*/

#define KEYMOVECURSOR 2/*光标移动键*/

#define KEYINVALID 3/*无效键*/

/*定义符号常量: 真, 假 --- 真为1, 假为0 */

#define TRUE 1

#define FALSE 0

/**********************************************************/

/* 定义数据结构 */

/*棋盘交叉点坐标的数据结构*/

struct point

{

int x,y

}

或者下面这个：

#include <graphics.h>

#include <stdlib.h>

#include <stdio.h>

#include <conio.h>

#define N 15

#define B 7

#define STOP -10000

#define OK 1

#define NO 0

#define UP 328

#define DOWN 336

#define LEFT 331

#define RIGHT 333

int a[N+1][N+1]

int zx,zy

int write=1,biaoji=0

struct zn{

long sum

int y

int x

}w[N+1][N+1],max,max1

void cbar(int i,int x,int y,int r)

void map(int a[][])

int getkey()

int key()

void zuobiao(int x,int y,int i)

int tu(int a[][],int write)

int wtu(int a[][],int write)

int zhineng(int a[][])

int zh5(int y,int x,int a[][])

long zzh5(int b[][],int i)

main()

{

int i,j

int gdriver=DETECT

int gmode

initgraph(&gdriver,&gmode,"")

zx=(N+1)/2

zy=(N+1)/2

for(i=1i<=Ni++)

for(j=1j<=Nj++)

a[i][j]=0

map(a)

i=1

while(i)

{

int k,n

k=wtu(a,write)

if(k==STOP) goto end

map(a)

n=zhineng(a)

if(n==STOP) goto end

map(a)

}

end:

}

int zhineng(int a[N+1][N+1])

{

int i,j

int k

max.sum=-1

for(i=0i<=Ni++)

for(j=0j<+Nj++)

{

w[i][j].sum=0

w[i][j].x=i

w[i][j].y=j

}

for(i=1i<=N-4i++)

for(j=1j<=N-4j++)

{

k=zh5(i,j,a)

if(k==STOP) return (STOP)

}

for(i=1i<=Ni++)

for(j=1j<=Nj++)

{

if(max.sum<w[i][j].sum)

{

max.sum=w[i][j].sum

max.y=i

max.x=j

}

else if(max.sum==w[i][j].sum)

{

if(((max.y-zy)*(max.y-zy)+(max.x-zx)*(max.x-zx))>((i-zy)*(i-zy)+(j-zx)*(j-zx)))

max.sum=w[i][j].sum

max.y=i

max.x=j

}

}

if(a[max.y][max.x]==0)

{

a[max.y][max.x]=-1

zy=max.y

zx=max.x

}

}

int zh5(int y,int x,int a[N+1][N+1])

{

int i,j

int b[6][6]

long c[13]

long d[6][6]

long temp

for(i=yi<=y+4i++)

for(j=xj<=x+4j++)

b[i+1-y][j+1-x]=a[i][j]

c[1]=b[1][1]+b[1][2]+b[1][3]+b[1][4]+b[1][5]

c[2]=b[2][1]+b[2][2]+b[2][3]+b[2][4]+b[2][5]

c[3]=b[3][1]+b[3][2]+b[3][3]+b[3][4]+b[3][5]

c[4]=b[4][1]+b[4][2]+b[4][3]+b[4][4]+b[4][5]

c[5]=b[5][1]+b[5][2]+b[5][3]+b[5][4]+b[5][5]

c[6]=b[1][1]+b[2][1]+b[3][1]+b[4][1]+b[5][1]

c[7]=b[1][2]+b[2][2]+b[3][2]+b[4][2]+b[5][2]

c[8]=b[1][3]+b[2][3]+b[3][3]+b[4][3]+b[5][3]

c[9]=b[1][4]+b[2][4]+b[3][4]+b[4][4]+b[5][4]

c[10]=b[1][5]+b[2][5]+b[3][5]+b[4][5]+b[5][5]

c[11]=b[1][1]+b[2][2]+b[3][3]+b[4][4]+b[5][5]

c[12]=b[1][5]+b[2][4]+b[3][3]+b[4][2]+b[5][1]

for(i=1i<=12i++)

{

switch(c[i])

{

case 5:biaoji=1return(STOP)

case -5:biaoji=-1return(STOP)

case -4:c[i]=100000break

case 4:c[i]=100000break

case -3:c[i]=150break

case 3:c[i]=150break

case -2:c[i]=120break

case 2:c[i]=100break

case -1:c[i]=1break

case 1:c[i]=1break

default: c[i]=0

}

}

for(i=1i<=12i++)

{

if(c[i]==150)

c[i]+=zzh5(b,i)

}

for(i=1i<=5i++)

for(j=1j<=5j++)

d[i][j]=0

for(i=1i<=5i++)

for(j=1j<=5j++)

{

if(i==j) d[i][j]+=c[11]

if((i+j)==6) d[i][j]+=c[12]

d[i][j]+=c[i]+c[j+5]

}

for(i=1i<=5i++)

for(j=1j<=5j++)

{

if(b[i][j]!=0)

d[i][j]=-2

}

max1.sum=-1

max1.y=0

max1.x=0

for(i=1i<=5i++)

for(j=1j<=5j++)

{

if(max1.sum<d[i][j])

{

max1.sum=d[i][j]

max1.y=i

max1.x=j

w[i+y-1][j+x-1].sum+=max1.sum

}

else if(max1.sum==d[i][j])

{

if(((i+y-1-zy)*(i+y-1-zy)+(j+x-1-zx)*(j+x-1-zx))>((max1.y+y-1-zy)*(max1.y+y-1-zy)+(max1.x+x-1-zx)*(max1.x+x-1-zx)))

{

max1.sum=d[i][j]

max1.y=i

max1.x=j

}

}

}

}

long zzh5(int b[6][6],int n)

{

int i,j,k,l,m

switch(n)

{

case 1:i=b[1][1]j=b[1][2]k=b[1][3]l=b[1][4]m=b[1][5]break

case 2:i=b[2][1]j=b[2][2]k=b[2][3]l=b[2][4]m=b[2][5]break

case 3:i=b[3][1]j=b[3][2]k=b[3][3]l=b[3][4]m=b[3][5]break

case 4:i=b[4][1]j=b[4][2]k=b[4][3]l=b[4][4]m=b[4][5]break

case 5:i=b[5][1]j=b[5][2]k=b[5][3]l=b[5][4]m=b[5][5]break

case 6:i=b[1][1]j=b[2][1]k=b[3][1]l=b[4][1]m=b[5][1]break

case 7:i=b[1][2]j=b[2][2]k=b[3][2]l=b[4][2]m=b[5][2]break

case 8:i=b[1][3]j=b[2][3]k=b[3][3]l=b[4][3]m=b[5][3]break

case 9:i=b[1][4]j=b[2][4]k=b[3][4]l=b[4][4]m=b[5][4]break

case 10:i=b[1][5]j=b[2][5]k=b[3][5]l=b[4][5]m=b[5][5]break

case 11:i=b[1][1]j=b[2][2]k=b[3][3]l=b[4][4]m=b[5][5]break

case 12:i=b[1][5]j=b[2][4]k=b[3][3]l=b[4][2]m=b[5][1]break

}

if((i==0&&j==1&&k==1&&l==1&&m==0))

return (900)

if((i==0&&j==-1&&k==-1&&l==-1&&m==0))

return(1000)

if((i==0&&j==0&&k==1&&l==1&&m==1)||(i==1&&j==1&&k==1&&l==0&&m==0))

return(20)

if((i==0&&j==0&&k==-1&&l==-1&&m==-1)||(i==-1&&j==-1&&k==-1&&l==0&&m==0))

return(20)

if((i==-1&&j==1&&k==1&&l==1&&m==1)||(i==1&&j==-1&&k==1&&l==1&&m==1)||(i==1&&j==1&&k==-1&&l==1&&m==1)||(i==1&&j==1&&k==1&&l==-1&&m==1)||(i==1&&j==1&&k==1&&l==1&&m==-1))

return(-60)

if((i==1&&j==-1&&k==-1&&l==-1&&m==-1)||(i==-1&&j==1&&k==-1&&l==-1&&m==-1)||(i==-1&&j==1&&k==-1&&l==-1&&m==-1)||(i==-1&&j==-1&&k==-1&&l==1&&m==-1)||(i==-1&&j==-1&&k==-1&&l==-1&&m==1))

return(-60)

}

int wtu(int a[N+1][N+1],int write)

{

int i=1

map(a)

zuobiao(zx,zy,1)

while(i)

{

int k

k=tu(a,write)

if(k==OK) i=0

if(k==STOP) return (STOP)

}

}

int getkey()

{

int key,lo,hi

key=bioskey(0)

lo=key&0x00ff

hi=(key&0xff00)>>8

return((lo==0) ? hi+256:lo)

}

int key()

{

int k

k=getkey()

switch(k)

{

case 27: return (STOP)

case 13:

case ' ': return (OK)

case 328: return (UP)

case 336: return (DOWN)

case 331: return (LEFT)

case 333: return (RIGHT)

default: return (NO)

}

}

void zuobiao(int x,int y,int i)

{

int r

if(i!=0)

{

setcolor(GREEN)

for(r=1r<=5r++)

circle(75+25*x,25+25*y,r)

}

else

{

if(a[zy][zx]==1)

{

setcolor(8)

for(r=1r<=5r++)

circle(75+25*x,25+25*y,r)

}

else if(a[zy][zx]==-1)

{

setcolor(WHITE)

for(r=1r<=5r++)

circle(75+25*x,25+25*y,r)

}

else

{

setcolor(B)

for(r=1r<=5r++)

circle(75+25*x,25+25*y,r)

setcolor(RED)line(75+25*zx-5,25+25*zy,75+25*x+5,25+25*zy)

line(75+25*zx,25+25*zy-5,75+25*zx,25+25*zy+5)

}

}

}

int tu(int a[N+1][N+1],int write)

{

int k

re:

k=key()

if(k==OK)

{

if(a[zy][zx]==0)

{

a[zy][zx]=write

}

else

goto re

}

if(k==STOP) return(STOP)

if(k==NO) goto re

if(k==UP)

{

int i,j

if(zy==1) j=zy

else j=zy-1

zuobiao(zx,zy,0)

zuobiao(zx,j,1)

zy=j

goto re

}

if(k==DOWN)

{

int i,j

if(zy==N) j=zy

else j=zy+1

zuobiao(zx,zy,0)

zuobiao(zx,j,1)

zy=j

goto re

}

if(k==LEFT)

{

int i,j

if(zx==1) i=zx

else i=zx-1

zuobiao(zx,zy,0)

zuobiao(i,zy,1)

zx=i

goto re

}

if(k==RIGHT)

{

int i,j

if(zx==N) i=zx

else i=zx+1

zuobiao(zx,zy,0)

zuobiao(i,zy,1)

zx=i

goto re

}

}

void cbar(int i,int x,int y,int r)

{

if(i!=0)

{

if(i==1)

setcolor(8)

else if(i==-1)

setcolor(WHITE)

for(i=1i<=ri++)

{

circle(x,y,i)

}

}

}

void map(int a[N+1][N+1])

{

int i,j

cleardevice()

setbkcolor(B)

setcolor(RED)

for(i=0i<Ni++)

{

line(100,50+25*i,75+N*25,50+25*i)

line(100+25*i,50,100+25*i,25+N*25)

}

for(i=1i<=Ni++)

for(j=1j<=Nj++)

cbar(a[i][j],75+25*j,25+25*i,10)

}

本程序设计为人与人对弈，双方有一方五子连成一线即为赢。设计一游戏变量（3到9之间），用来控制显示面板的大小，即用户可选择生成3×3到9×9的棋盘。

五子棋C语言代码如下：#include <stdio.h>#include <bios.h>#include <ctype.h>#include <conio.h>#include <dos.h>#define CROSSRU 0xbf /*右上角点*/#define CROSSLU 0xda /*左上角点*/#define CROSSLD 0xc0 /*左下角点*/#define CROSSRD 0xd9 /*右下角点*/#define CROSSL 0xc3 /*左边*/#define CROSSR 0xb4 /*右边*/#define CROSSU 0xc2 /*上边*/#define CROSSD 0xc1 /*下边*/#define CROSS 0xc5 /*十字交叉点*//*定义棋盘左上角点在屏幕上的位置*/#define MAPXOFT 5#define MAPYOFT 2/*定义1号玩家的 *** 作键键码*/#define PLAY1UP 0x1157/*上移--'W'*/#define PLAY1DOWN 0x1f53/*下移--'S'*/#define PLAY1LEFT 0x1e41/*左移--'A'*/#define PLAY1RIGHT 0x2044/*右移--'D'*/#define PLAY1DO 0x3920/*落子--空格键*//*定义2号玩家的 *** 作键键码*/#define PLAY2UP 0x4800/*上移--方向键up*/#define PLAY2DOWN 0x5000/*下移--方向键down*/#define PLAY2LEFT 0x4b00/*左移--方向键left*/#define PLAY2RIGHT 0x4d00/*右移--方向键right*/#define PLAY2DO 0x1c0d/*落子--回车键Enter*//*若想在游戏中途退出, 可按 Esc 键*/#define ESCAPE 0x011b/*定义棋盘上交叉点的状态, 即该点有无棋子 *//*若有棋子, 还应能指出是哪个玩家的棋子 */#define CHESSNULL 0 /*没有棋子*/#define CHESS1 'O'/*一号玩家的棋子*/#define CHESS2 'X'/*二号玩家的棋子*//*定义按键类别*/#define KEYEX99v 0/*退出键*/#define KEYFALLCHESS 1/*落子键*/#define KEYMOVECURSOR 2/*光标移动键*/#define KEYINVALID 3/*无效键*//*定义符号常量: 真, 假 --- 真为1, 假为0 */#define TRUE 1#define FALSE 0/**********************************************************//* 定义数据结构 *//*棋盘交叉点坐标的数据结构*/struct point{int x,y}或者下面这个：#include <graphics.h>#include <stdlib.h>#include <stdio.h>#include <conio.h>#define N 15#define B 7#define STOP -10000#define OK 1#define NO 0#define UP 328#define DOWN 336#define LEFT 331#define RIGHT 333int a[N+1][N+1]int zx,zyint write=1,biaoji=0struct zn{long sumint yint x}w[N+1][N+1],max,max1void cbar(int i,int x,int y,int r)void map(int a[][])int getkey()int key()void zuobiao(int x,int y,int i)int tu(int a[][],int write)int wtu(int a[][],int write)int zhineng(int a[][])int zh5(int y,int x,int a[][])long zzh5(int b[][],int i)main(){int i,jint gdriver=DETECTint gmodeinitgraph(&gdriver,&gmode,"")zx=(N+1)/2zy=(N+1)/2for(i=1i<=Ni++)for(j=1j<=Nj++)a[i][j]=0map(a)i=1while(i){int k,nk=wtu(a,write)if(k==STOP) goto endmap(a)n=zhineng(a)if(n==STOP) goto endmap(a)}end:}int zhineng(int a[N+1][N+1]){int i,jint kmax.sum=-1for(i=0i<=Ni++)for(j=0j<+Nj++){w[i][j].sum=0w[i][j].x=iw[i][j].y=j}for(i=1i<=N-4i++)for(j=1j<=N-4j++){k=zh5(i,j,a)if(k==STOP) return (STOP)}for(i=1i<=Ni++)for(j=1j<=Nj++){if(max.sum<w[i][j].sum){max.sum=w[i][j].summax.y=imax.x=j}else if(max.sum==w[i][j].sum){if(((max.y-zy)*(max.y-zy)+(max.x-zx)*(max.x-zx))>((i-zy)*(i-zy)+(j-zx)*(j-zx)))max.sum=w[i][j].summax.y=imax.x=j}}if(a[max.y][max.x]==0){a[max.y][max.x]=-1zy=max.yzx=max.x}}int zh5(int y,int x,int a[N+1][N+1]){int i,jint b[6][6]long c[13]long d[6][6]long tempfor(i=yi<=y+4i++)for(j=xj<=x+4j++)b[i+1-y][j+1-x]=a[i][j]c[1]=b[1][1]+b[1][2]+b[1][3]+b[1][4]+b[1][5]c[2]=b[2][1]+b[2][2]+b[2][3]+b[2][4]+b[2][5]c[3]=b[3][1]+b[3][2]+b[3][3]+b[3][4]+b[3][5]c[4]=b[4][1]+b[4][2]+b[4][3]+b[4][4]+b[4][5]c[5]=b[5][1]+b[5][2]+b[5][3]+b[5][4]+b[5][5]c[6]=b[1][1]+b[2][1]+b[3][1]+b[4][1]+b[5][1]c[7]=b[1][2]+b[2][2]+b[3][2]+b[4][2]+b[5][2]c[8]=b[1][3]+b[2][3]+b[3][3]+b[4][3]+b[5][3]c[9]=b[1][4]+b[2][4]+b[3][4]+b[4][4]+b[5][4]c[10]=b[1][5]+b[2][5]+b[3][5]+b[4][5]+b[5][5]c[11]=b[1][1]+b[2][2]+b[3][3]+b[4][4]+b[5][5]c[12]=b[1][5]+b[2][4]+b[3][3]+b[4][2]+b[5][1]for(i=1i<=12i++){switch(c[i]){case 5:biaoji=1return(STOP)case -5:biaoji=-1return(STOP)case -4:c[i]=100000breakcase 4:c[i]=100000breakcase -3:c[i]=150breakcase 3:c[i]=150breakcase -2:c[i]=120breakcase 2:c[i]=100breakcase -1:c[i]=1breakcase 1:c[i]=1breakdefault: c[i]=0}}for(i=1i<=12i++){if(c[i]==150)c[i]+=zzh5(b,i)}for(i=1i<=5i++)for(j=1j<=5j++)d[i][j]=0for(i=1i<=5i++)for(j=1j<=5j++){if(i==j) d[i][j]+=c[11]if((i+j)==6) d[i][j]+=c[12]d[i][j]+=c[i]+c[j+5]}for(i=1i<=5i++)for(j=1j<=5j++){if(b[i][j]!=0)d[i][j]=-2}max1.sum=-1max1.y=0max1.x=0for(i=1i<=5i++)for(j=1j<=5j++){if(max1.sum<d[i][j]){max1.sum=d[i][j]max1.y=imax1.x=jw[i+y-1][j+x-1].sum+=max1.sum}else if(max1.sum==d[i][j]){if(((i+y-1-zy)*(i+y-1-zy)+(j+x-1-zx)*(j+x-1-zx))>((max1.y+y-1-zy)*(max1.y+y-1-zy)+(max1.x+x-1-zx)*(max1.x+x-1-zx))){max1.sum=d[i][j]max1.y=imax1.x=j}}}}long zzh5(int b[6][6],int n){int i,j,k,l,mswitch(n){case 1:i=b[1][1]j=b[1][2]k=b[1][3]l=b[1][4]m=b[1][5]breakcase 2:i=b[2][1]j=b[2][2]k=b[2][3]l=b[2][4]m=b[2][5]breakcase 3:i=b[3][1]j=b[3][2]k=b[3][3]l=b[3][4]m=b[3][5]breakcase 4:i=b[4][1]j=b[4][2]k=b[4][3]l=b[4][4]m=b[4][5]breakcase 5:i=b[5][1]j=b[5][2]k=b[5][3]l=b[5][4]m=b[5][5]breakcase 6:i=b[1][1]j=b[2][1]k=b[3][1]l=b[4][1]m=b[5][1]breakcase 7:i=b[1][2]j=b[2][2]k=b[3][2]l=b[4][2]m=b[5][2]breakcase 8:i=b[1][3]j=b[2][3]k=b[3][3]l=b[4][3]m=b[5][3]breakcase 9:i=b[1][4]j=b[2][4]k=b[3][4]l=b[4][4]m=b[5][4]breakcase 10:i=b[1][5]j=b[2][5]k=b[3][5]l=b[4][5]m=b[5][5]breakcase 11:i=b[1][1]j=b[2][2]k=b[3][3]l=b[4][4]m=b[5][5]breakcase 12:i=b[1][5]j=b[2][4]k=b[3][3]l=b[4][2]m=b[5][1]break}if((i==0&&j==1&&k==1&&l==1&&m==0))return (900)if((i==0&&j==-1&&k==-1&&l==-1&&m==0))return(1000)if((i==0&&j==0&&k==1&&l==1&&m==1)||(i==1&&j==1&&k==1&&l==0&&m==0))return(20)if((i==0&&j==0&&k==-1&&l==-1&&m==-1)||(i==-1&&j==-1&&k==-1&&l==0&&m==0))return(20)if((i==-1&&j==1&&k==1&&l==1&&m==1)||(i==1&&j==-1&&k==1&&l==1&&m==1)||(i==1&&j==1&&k==-1&&l==1&&m==1)||(i==1&&j==1&&k==1&&l==-1&&m==1)||(i==1&&j==1&&k==1&&l==1&&m==-1))return(-60)if((i==1&&j==-1&&k==-1&&l==-1&&m==-1)||(i==-1&&j==1&&k==-1&&l==-1&&m==-1)||(i==-1&&j==1&&k==-1&&l==-1&&m==-1)||(i==-1&&j==-1&&k==-1&&l==1&&m==-1)||(i==-1&&j==-1&&k==-1&&l==-1&&m==1))return(-60)}int wtu(int a[N+1][N+1],int write){int i=1map(a)zuobiao(zx,zy,1)while(i){int kk=tu(a,write)if(k==OK) i=0if(k==STOP) return (STOP)}}int getkey(){int key,lo,hikey=bioskey(0)lo=key&0x00ffhi=(key&0xff00)>>8return((lo==0) ? hi+256:lo)}int key(){int kk=getkey()switch(k){case 27: return (STOP)case 13:case ' ': return (OK)case 328: return (UP)case 336: return (DOWN)case 331: return (LEFT)case 333: return (RIGHT)default: return (NO)}}void zuobiao(int x,int y,int i){int rif(i!=0){setcolor(GREEN)for(r=1r<=5r++)circle(75+25*x,25+25*y,r)}else{if(a[zy][zx]==1){setcolor(8)for(r=1r<=5r++)circle(75+25*x,25+25*y,r)}else if(a[zy][zx]==-1){setcolor(WHITE)for(r=1r<=5r++)circle(75+25*x,25+25*y,r)}else{setcolor(B)for(r=1r<=5r++)circle(75+25*x,25+25*y,r)setcolor(RED)line(75+25*zx-5,25+25*zy,75+25*x+5,25+25*zy)line(75+25*zx,25+25*zy-5,75+25*zx,25+25*zy+5)}}}int tu(int a[N+1][N+1],int write){int kre:k=key()if(k==OK){if(a[zy][zx]==0){a[zy][zx]=write}elsegoto re}if(k==STOP) return(STOP)if(k==NO) goto reif(k==UP){int i,jif(zy==1) j=zyelse j=zy-1zuobiao(zx,zy,0)zuobiao(zx,j,1)zy=jgoto re}if(k==DOWN){int i,jif(zy==N) j=zyelse j=zy+1zuobiao(zx,zy,0)zuobiao(zx,j,1)zy=jgoto re}if(k==LEFT){int i,jif(zx==1) i=zxelse i=zx-1zuobiao(zx,zy,0)zuobiao(i,zy,1)zx=igoto re}if(k==RIGHT){int i,jif(zx==N) i=zxelse i=zx+1zuobiao(zx,zy,0)zuobiao(i,zy,1)zx=igoto re}}void cbar(int i,int x,int y,int r){if(i!=0){if(i==1)setcolor(8)else if(i==-1)setcolor(WHITE)for(i=1i<=ri++){circle(x,y,i)}}}void map(int a[N+1][N+1]){int i,jcleardevice()setbkcolor(B)setcolor(RED)for(i=0i<Ni++){line(100,50+25*i,75+N*25,50+25*i)line(100+25*i,50,100+25*i,25+N*25)}for(i=1i<=Ni++)for(j=1j<=Nj++)cbar(a[i][j],75+25*j,25+25*i,10)}