var a, b, c, d, e, f, g, h, i, j: semaphore: =0,0,0,0,0,0,0,0,0,0
begin S1signal(a)signal(b)end
begin wait(a)S2signal(c)signal(d)end
begin wait(b)S3signal(e)signal(f)end
begin wait(c)S4signal(g)end
begin wait(d)S5signal(h)end
begin wait(e)S6signal(i)end
begin wait(f)S7signal(j)end
begin wait(g)wait(h)wait(i)wait(j)S8end
如果不空此是这明含图,类似的 也可激亏笑以自己敲
#include <stdio.h>升埋和吵盯#include <ctype.h>液枝
int main()
{
int c
FILE *fp
if ((fp = fopen("mytext.txt", "rt")) == NULL)
{
fprintf(stderr, "open file failure!\n")
return 1
}
while ((c = fgetc(fp)) != EOF)
putchar(toupper(c))
return 0
}
#include <stdio.h>#include "伏孝stdlib.h"
#include <iostream>
using namespace std
int main()
{
int a[111], k = 0, n, x = 0
do {
scanf_s("%d", &a[k])
k++
} while (getchar() != '铅纯\n')
scanf_s("%d", &n)
cout <<k <<endl
for (int i = 0i <ki++)
{
if (a[i] == n) {
x = 1
break
}
}
if (x == 0) {
cout <<k <<endl
a[k] = 99
a[k + 1] = '\n'
k++
cout <缺激稿<k <<endl
}
for (int i = 0i <ki++)
printf("%d ", a[i])
system("pause")
}
欢迎分享,转载请注明来源:内存溢出
评论列表(0条)