java事件处理button如何单击按钮退出

如果是要实现单击按钮退出，建议删掉这行态腊代码绝樱：

if(e.getActionCommand().equals("Eixt"))

或者，将实现接口的两个类变为public的内部类，同时稍微修改下，如下

import java.awt.*

import java.awt.event.*

public class lesson1 {

private Frame f

private Button b

public lesson1() {

f = new Frame("event")

b = new Button("Exit"帆宏滑)

}

public void launchFrame() {

b.addMouseListener(new ButtonHandler())

f.addWindowListener(new ClosingHander())

f.add(b, BorderLayout.CENTER)

f.setSize(400, 300)

f.setVisible(true)

f.setVisible(true)

f.setSize(400, 300)

}

public static void main(String args[]) {

lesson1 aa = new lesson1()

aa.launchFrame()

}

class ButtonHandler extends MouseAdapter {

public void mouseClicked(MouseEvent e)

{

if (e.getSource() == b) {

System.exit(0)

}

}

}

class ClosingHander extends WindowAdapter {

public void windowClosing(WindowEvent e) {

System.exit(0)

}

}

}

给按钮添加 ActionPerform 事件 内容写System.exit（0）；

package com.lx

import java.awt.Button

import java.awt.FlowLayout

import java.awt.Frame

import java.awt.event.ActionEvent

import java.awt.event.ActionListener

public class Test implements ActionListener {

Frame f = new Frame()

public static void main(String[] args) {

Test t = new Test()

t.init()

}

private void init() {

Button b = new Button("exit")

b.addActionListener(this)

f.add(b)

f.setLayout(new FlowLayout())

f.setSize(100,100)

f.setVisible(true)

}

public void actionPerformed(ActionEvent arg0) {

f.setVisible(false)

f.dispose()

System.exit(0)

}

}

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