for (( i=1i<=9i++))
do
for (( j=1j<=ij++))
do
echo -n $j*$i=$((i*j))
[ $((i*j)) -lt 10 ] &&echo -n " " || echo -n " " #10以内两个空格,大于10一个空格,第一对引号里面两个空格(百度会合并空格)
done
echo
done
写一个在是C下实现的啊#include<stdio.h>
int main(void)
{
int i,j
int a[10][10]
for(i=1i<=9i++){
for(j=ij<=9j++){
a[i][j]=i*j
}
}
for(i=1i<=9i++){
for(j=ij<=9j++){
printf("%dx%d=%d ",i,j,a[i][j])
}
printf("\n")
}
return 0
}
参考代码:
<%@ page language="java" contentType="text/html charset=UTF-8"pageEncoding="UTF-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html charset=UTF-8">
<title>九九乘法表</title>
</head>
<body>
<%
for (int i = 1 i <= 9 i++) {
for (int j = 1 j <= i j++) {
out.print(j + "×" + i + "=" + (i * j) + "&nbsp &nbsp ")
}
out.print("<br>")
}
%>
</body>
</html>
运行效果:
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