如何用C语言编一个彩票15选5并显示所有排列组合的程序。

已调试完毕,共3003条!!!每输出40条按任一键继续...,保证结果万无一失,你可以查看下,源程序如下:

#include "stdio.h"

main()

{int i,j,k,m,n

long int count=0

for(i=1i<=15i++)

for(j=i+1j<=15j++)

for(k=j+1k<=15k++)

for(m=k+1m<=15m++)

for(n=m+1n<=15n++)

{if(iden(i,j,k,m,n))

printf("No %ld : %5d%5d%5d%5d%5d\n",++count,i,j,k,m,n)

if(count%45==0) getchar()

}

}

iden(int i,int j,int k,int m,int n)

{if(i==j||i==k||i==m||i==n||j==k||j==m||j==n||k==m||k==n||m==n)

return 0

else

return 1

}

再增加两个变量,修改下程序可以35选5,我机子是P4 cpu1.8G 内存是512M,跑了好久,估计要两个小时左右!!!没耐心等下去,有朋友想试下的我把程序弄下面来了!!

#include "stdio.h"

main()

{int i,j,k,m,n,q,w

long int count=0

for(i=1i<=35i++)

for(j=i+1j<=35j++)

for(k=j+1k<=35k++)

for(m=k+1m<=35m++)

for(n=m+1n<=35n++)

for(q=n+1q<=35q++)

for(w=q+1w<=35w++)

{if(iden(i,j,k,m,n,q,w))

printf("No %ld : %5d%5d%5d%5d%5d%5d%5d\n",++count,i,j,k,m,n,q,w)

if(count%45==0) getchar()

}

}

iden(int i,int j,int k,int m,int n,int q,int w)

{if(i==j||i==k||i==m||i==n||i==q||i==w||j==k||j==m||j==n||j==q||j==w||k==m||k==n||k==q||k==w||m==n||m==q||m==w||n==q||n==w||q==w)

return 0

else

return 1

}

namespace Test

{

class Program

{

static void Main(string[] args)

{

ICaiPiao cp = new CaiPiao()

List<int>numbers = cp.Extract()

string x = string.Empty foreach (int i in numbers)

{

x += " " + i.ToString()

}

Console.Write(x)

Console.Read()

}

}

interface ICaiPiao

{

List<int>Extract()

}

class CaiPiao : ICaiPiao

{

private List<int>numberspublic List<int>Extract()

{

List<int>numbers = new List<int>() NumberEntity[] ns = new NumberEntity[31]

for (int i = 0i <31i++)

{

ns[i] = new NumberEntity()

ns[i].Value = i + 1

ns[i].Selected = false

}

Random r = new Random()

do

{

int index = r.Next(0, 30)

if (!ns[index].Selected)

{

numbers.Add(ns[index].Value)

ns[index].Selected = true

}

} while (numbers.Count <7)

return numbers }

}

class NumberEntity

{

private int _Value public int Value

{

get { return _Value}

set { _Value = value}

}private bool _Selected public bool Selected

{

get { return _Selected}

set { _Selected = value}

}

}

}

我自己敲的 觉得好 就给点分把

#include <stdio.h>

main()

{

int p[7],q[7],n,i/****p:投注号码，q:开奖号码****/

char c='0'

st(p,q)/****初始化****/

n=pd(p,q)

switch (n)

{

case 6:

{

if(p[6]==q[6]) c='!'

else c='1'

} break

case 5:

{

if(p[1]!=q[1]||p[4]!=q[4]) c='3'

if(p[2]!=q[2]||p[3]!=q[3]) c='0'

else c='2'

} break

case 4:

{

if((p[0]!=q[0]&&p[1]!=q[1])||(p[0]!=q[0]&&p[5]!=q[5])||(p[4]!=q[4]&&p[5]!=q[5]))

c='3'

else c='0'

}

}

switch (c )

{

case '!': printf("\nni zhong le te deng jiang!")break

case '1': printf("\nni zhong le 1 deng jiang!")break

case '2': printf("\nni zhong le 2 deng jiang!")break

case '3': printf("\nni zhong le 3 deng jiang!")break

case '0': printf("\nni mei you zhong jiang!")break

}

getch()

}

st(int p[],int q[])

{

int i

printf("\nXuan zhe tou zhu hao ma: ")

for(i=0i<7i++)

scanf("%d",&p[i])

printf("\nKai jiang hao ma shi: ")

for(i=0i<7i++)

scanf("%d",&q[i])

}

pd(int p[],int q[])

{

int i,n=0

for(i=0i<6i++)

if(p[i]==q[i])

n++

return(n)

}

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