c语言如何编写一个简单的多线程程序？

这是一个多线程例子，里面只有两个线程，是生产者/消费者模式，已编译通过，注释很详细，\x0d\x0a如下：\x0d\x0a\x0d\x0a/* 以生产者和消费者模型问题来阐述Linux线程的控制和通信你 \x0d\x0a生产者线程将生产的产品送入缓冲区，消费者线程则从中取出产品。\x0d\x0a缓冲区有N个，是一个环形的缓冲池。\x0d\x0a*/\x0d\x0a#include \x0d\x0a#include \x0d\x0a\x0d\x0a#define BUFFER_SIZE 16\x0d\x0a\x0d\x0astruct prodcons\x0d\x0a{\x0d\x0aint buffer[BUFFER_SIZE]/*实际存放数据的数组*/\x0d\x0apthread_mutex_t lock/*互斥体lock，用于对缓冲区的互斥 *** 作*/\x0d\x0aint readpos,writepos/*读写指针*/\x0d\x0apthread_cond_t notempty/*缓冲区非空的条件变量*/\x0d\x0apthread_cond_t notfull/*缓冲区未满 的条件变量*/\x0d\x0a}\x0d\x0a\x0d\x0a/*初始化缓冲区*/\x0d\x0avoid pthread_init( struct prodcons *p)\x0d\x0a{\x0d\x0apthread_mutex_init(&p->lock,NULL)\x0d\x0apthread_cond_init(&p->notempty,NULL)\x0d\x0apthread_cond_init(&p->notfull,NULL)\x0d\x0ap->readpos = 0\x0d\x0ap->writepos = 0\x0d\x0a}\x0d\x0a\x0d\x0a/*将产品放入缓冲区，这里是存入一个整数*/\x0d\x0avoid put(struct prodcons *p,int data)\x0d\x0a{\x0d\x0apthread_mutex_lock(&p->lock)\x0d\x0a/*等待缓冲区未满*/\x0d\x0aif((p->writepos +1)%BUFFER_SIZE ==p->readpos)\x0d\x0a{\x0d\x0apthread_cond_wait(&p->notfull,&p->lock)\x0d\x0a}\x0d\x0ap->buffer[p->writepos] =data\x0d\x0ap->writepos++\x0d\x0aif(p->writepos >= BUFFER_SIZE)\x0d\x0ap->writepos = 0\x0d\x0apthread_cond_signal(&p->notempty)\x0d\x0apthread_mutex_unlock(&p->lock)\x0d\x0a}\x0d\x0a/*从缓冲区取出整数*/\x0d\x0aint get(struct prodcons *p)\x0d\x0a{\x0d\x0aint data\x0d\x0apthread_mutex_lock(&p->lock)\x0d\x0a/*等待缓冲区非空*/\x0d\x0aif(p->writepos == p->readpos)\x0d\x0a{\x0d\x0apthread_cond_wait(&p->notempty ,&p->lock)//非空就设置条件变量notempty\x0d\x0a}\x0d\x0a/*读书据，移动读指针*/\x0d\x0adata = p->buffer[p->readpos]\x0d\x0ap->readpos++\x0d\x0aif(p->readpos == BUFFER_SIZE)\x0d\x0ap->readpos = 0\x0d\x0a/*设置缓冲区未满的条件变量*/\x0d\x0apthread_cond_signal(&p->notfull)\x0d\x0apthread_mutex_unlock(&p->lock)\x0d\x0areturn data\x0d\x0a}\x0d\x0a /*测试：生产站线程将1 到1000的整数送入缓冲区，消费者线程从缓冲区中获取整数，两者都打印信息*/\x0d\x0a#define OVER (-1)\x0d\x0astruct prodcons buffer\x0d\x0avoid *producer(void *data)\x0d\x0a{\x0d\x0aint n\x0d\x0afor( n=0n\n",n)\x0d\x0aput(&buffer,n)\x0d\x0a}\x0d\x0aput(&buffer,OVER)\x0d\x0areturn NULL\x0d\x0a}\x0d\x0avoid *consumer(void *data)\x0d\x0a{\x0d\x0aint d\x0d\x0awhile(1)\x0d\x0a{\x0d\x0ad = get(&buffer)\x0d\x0aif(d == OVER)\x0d\x0abreak\x0d\x0aelse\x0d\x0aprintf("----->%d\n",d)\x0d\x0a}\x0d\x0areturn NULL\x0d\x0a}\x0d\x0aint main()\x0d\x0a{\x0d\x0apthread_t th_p,th_c\x0d\x0avoid *retval\x0d\x0a pthread_init(&buffer)\x0d\x0apthread_create(&th_p,NULL,producer,0)\x0d\x0apthread_create(&th_c,NULL,consumer,0)\x0d\x0a/*等待两个线程结束*/\x0d\x0a pthread_join(th_p, &retval)\x0d\x0a pthread_join(th_c,&retval)\x0d\x0a return 0\x0d\x0a}

多线程实际上就是多个线程同时运行，至于那个先完成是不能确定的。

* @author Rollen-Holt 实现Runnable接口

* */

class hello implements Runnable {

 public hello() {

 }

 public hello(String name) {

     this.name = name

 }

 public void run() {

     for (int i = 0i <5i++) {

         System.out.println(name + "运行     " + i)

     }

 }

 public static void main(String[] args) {

     hello h1=new hello("线程A")

     Thread demo= new Thread(h1)

     hello h2=new hello("线程B")

     Thread demo1=new Thread(h2)

     demo.start()

     demo1.start()

 }

 private String name

}

可能运行结果：

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