完整示例:
private static final Pattern p = Pattern.compile("^([a-zA-Z]+)([0-9]+)(.*)");public static void main(String[] args) { // create matcher for pattern p and given string Matcher m = p.matcher("Testing123Testing"); // if an occurrence if a pattern was found in a given string... if (m.find()) { // ...then you can use group() methods. System.out.println(m.group(0)); // whole matched expression System.out.println(m.group(1)); // first expression from round brackets (Testing) System.out.println(m.group(2)); // second one (123) System.out.println(m.group(3)); // third one (Testing) }}
由于你要查找第一个数字,因此可以使用以下正则表达式:
^D+(d+).*
并
m.group(1)会返回你的第一个电话号码。请注意,带符号的数字可以包含减号:
^D+(-?d+).*
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