问题是您要从要迭代的对象中删除元素,当删除元素时,其余元素会发生移动,因此最终可能会删除不正确的元素:
一个简单的解决方案是遍历树的副本或使用 reversed :
复制:
def processGroup(group): # creates a shallow copy so we are removing from the original # but iterating over a copy. for e in group[:]: if e.tag != 'a': group.remove(e) showGroup(group,'removed <' + e.tag + '>')
反转:
def processGroup(group): # starts at the end, as the container shrinks. # when an element is removed, we still see # elements at the same position when we started out loop. for e in reversed(group): if e.tag != 'a': group.remove(e) showGroup(group,'removed <' + e.tag + '>')
使用复制逻辑:
In [7]: tree = ET.parse('test.xml')In [8]: root = tree.getroot()In [9]: for group in root: ...: processGroup(group) ...: removed <b> len=2<group> <a> <c></group>removed <c> len=1<group> <a></group>
您也可以使用
ET.tostringfor循环代替:
import xml.etree.ElementTree as ETdef show_group(group,s): print(s + ' len=' + str(len(group))) print(ET.tostring(group))def process_group(group): for e in group[:]: if e.tag != 'a': group.remove(e) show_group(group, 'removed <' + e.tag + '>')tree = ET.parse('test.xml')root = tree.getroot()for group in root.findall(".//group"): process_group(group)
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