如何获取开始菜单的程序目录的路径？

如何获取开始菜单的程序目录的路径？

一位朋友，Environment.gov.au的Luke Pinner通过电子邮件提供了一个使用核心模块（python
2.5+）的解决方案。由于API调用返回的是unipre，因此被认为是多语言的。在具有日语语言环境的Win7上进行了测试，并在另一台美国英语计算机上通过手动将“开始”菜单更改为指向
％USERPROFILE％Startmenü进行了测试

''' Get windows special folders without pythonwin    Example: import specialfolders start_programs = specialfolders.get(specialfolders.PROGRAMS)Code is public domain, do with it what you will.Luke Pinner - Environment.gov.au, 2010 February 10'''#imports use _syntax to mask them from autocomplete IDE'simport ctypes as _ctypesfrom ctypes.wintypes import HWND as _HWND, HANDLE as _HANDLE,DWORD as _DWORD,LPCWSTR as _LPCWSTR,MAX_PATH as _MAX_PATH, create_unipre_buffer as _cub_SHGetFolderPath = _ctypes.windll.shell32.SHGetFolderPathW#public special folder constantsDESKTOP=       0PROGRAMS=      2MYdocumentS=   5FAVORITES=     6STARTUP=       7RECENT=        8SENDTO=        9STARTMENU=    11MYMUSIC=      13MYVIDEOS=     14NETHOOD=      19FonTS=        20TEMPLATES=    21ALLUSERSSTARTMENU=       22ALLUSERSPROGRAMS=        23ALLUSERSSTARTUP=         24ALLUSERSDESKTOP=         25APPLICATIonDATA=         26PRINTHOOD=    27LOCALSETTINGSAPPLICATIonDATA=       28ALLUSERSFAVORITES=       31LOCALSETTINGSTEMPORARYINTERNETFILES=32cookieS=      33LOCALSETTINGSHISTORY=    34ALLUSERSAPPLICATIonDATA= 35def get(intFolder):    _SHGetFolderPath.argtypes = [_HWND, _ctypes.c_int, _HANDLE, _DWORD, _LPCWSTR]    auPathBuffer = _cub(_MAX_PATH)    exit_pre=_SHGetFolderPath(0, intFolder, 0, 0, auPathBuffer)    return auPathBuffer.value