您将如何使此Python词典具有线程安全性？

如果您需要锁（以避免Joonas描述的竞争条件），并且坚持使用Python 2.4，

import threadinglock = threading.Lock()shared_dict = {}def do_thing(user, value):    lock.acquire()    try:        shared_dict[user] = value    finally:        # Always called, even if exception is raised in try block        lock.release()