MySql获取某一天每个小时的数据

select hour(create_time) AS saleHour, count(id) AS saleCount

from tableName where date_format(create_time, ‘%Y-%m-%d’ ) = ‘2021-09-07’

group by hour(create_time)

N列可以用这个公式=((HOUR(M2)-HOUR(L2))*60+(MINUTE(M2)-MINUTE(L2)))例如 我下面的表格 我的列是M 和L列时间差  精算分钟  如果你复制过去 那就修改对应公式里的对应的列

时间段统计，可以采用 hour(subscribe_time) 取出小时然后分层。思路：

select

uid

,CASE WHEN HOUR(subscribe_time) BETWEEN 0 AND 1 THEN '00:00:00'

WHEN HOUR(subscribe_time) BETWEEN 2 AND 3 THEN '02:00:00'

...

ELSE '23:00:00' END -- 生成时间分层部分，insert前外层sql加上日期后作为唯一的时间值

,COUNT(*)

FROM yht_fans WHERE subscribe_time>=UNIX_TIMESTAMP(CURDATE()) and subscribe_time<=UNIX_TIMESTAMP(CURDATE())+86400

GROUP BY 1,2

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