--添加一条记录
INSERT INTO tableName(col1,col2,col3) VALUES (1,2,3)
--添加多条记录
INSERT INTO tableName(col1,col2,col3)
SELECT 3,4,5
UNION ALL
SELECT 6,7,8
--从另外的一张表中读取多条数据添加到新表中
INSERT INTO tableName(col1,col2,col3)
SELECT a,b,c FROM tableA
--从其他的多张表中读取数据添加到新表中
INSERT INTO tableName(col1,col2,col3)
SELECT a,b,c FROM tableA WHERE a=1
UNION ALL
SELECT a,b,c FROM tableB WHERE a=2
上边代码中的into都可以省略！
上边代码中的union all如果换成union，则相同记录只插入一次，不会重复插入。
另外一种方法是SQL Server2008特有的，所以，如果你不是SQL Server2008，就不能使用这种方法了。
INSERT INTO MyTable(ID,NAME)VALUES(7,'003'),(8,'004'),(9,'005')
create table [TEST]
(
[NUM_ID] int primary key
)
go
declare @temp int
set @temp=1
while @temp<=1000000
begin
insert into [TEST]([NUM_ID]) values(@temp)
set @temp=@temp+1
end
go
----------------------------------------------------------
--试试下面的方法
--2005
DECLARE @n AS BIGINT
SET @n = 1000000
WITH Base AS
(
SELECT 1 AS n
UNION ALL
SELECT n + 1 FROM Base WHERE n <CEILING(SQRT(@n))
),
Expand AS
(
SELECT 1 AS c
FROM Base AS B1, Base AS B2
),
Nums AS
(
SELECT ROW_NUMBER() OVER(ORDER BY c) AS n
FROM Expand
)
SELECT n FROM Nums WHERE n <= @n
OPTION(MAXRECURSION 0)
--2
CREATE FUNCTION dbo.fn_nums(@n AS BIGINT) RETURNS TABLE
AS
RETURN
WITH
L0 AS(SELECT 1 AS c UNION ALL SELECT 1),
L1 AS(SELECT 1 AS c FROM L0 AS A, L0 AS B),
L2 AS(SELECT 1 AS c FROM L1 AS A, L1 AS B),
L3 AS(SELECT 1 AS c FROM L2 AS A, L2 AS B),
L4 AS(SELECT 1 AS c FROM L3 AS A, L3 AS B),
L5 AS(SELECT 1 AS c FROM L4 AS A, L4 AS B),
Nums AS(SELECT ROW_NUMBER() OVER(ORDER BY c) AS n FROM L5)
SELECT n FROM Nums WHERE n <= @n
GO
--2000 这个会比前两个慢，但是前两个2000不能用
CREATE TABLE dbo.Nums(n INT NOT NULL PRIMARY KEY)
DECLARE @max AS INT, @rc AS INT
SET @max = 1000000
SET @rc = 1
INSERT INTO Nums VALUES(1)
WHILE @rc * 2 <= @max
BEGIN
INSERT INTO dbo.Nums SELECT n + @rc FROM dbo.Nums
SET @rc = @rc * 2
END
INSERT INTO dbo.Nums
SELECT n + @rc FROM dbo.Nums WHERE n + @rc <= @max
--------------------------------------------------------------------------------------------------------
在使用sql数据库的时候，我们也许会需要一次像数据库中添加多条记录，那么我们可以使用sql语句来实现，该语句具体如下：--添加一条记录
insert
into
tablename(col1,col2,col3)
values
(1,2,3)
--添加多条记录
insert
into
tablename(col1,col2,col3)
select
3,4,5
union
all
select
6,7,8
--从另外的一张表中读取多条数据添加到新表中
insert
into
tablename(col1,col2,col3)
select
a,b,c
from
tablea
--从其他的多张表中读取数据添加到新表中
insert
into
tablename(col1,col2,col3)
select
a,b,c
from
tablea
where
a=1
union
all
select
a,b,c
from
tableb
where
a=2
上边代码中的into都可以省略！
上边代码中的union
all如果换成union，则相同记录只插入一次，不会重复插入。
另外一种方法是sql
server2008特有的，所以，如果你不是sql
server2008，就不能使用这种方法了。
insert
into
mytable(id,name)values(7,'003'),(8,'004'),(9,'005')
create
table
[test]
(
[num_id]
int
primary
key
)
go
declare
@temp
int
set
@temp=1
while
@temp<=1000000
begin
insert
into
[test]([num_id])
values(@temp)
set
@temp=@temp+1
end
go
----------------------------------------------------------
--试试下面的方法
--2005
declare
@n
as
bigint
set
@n
=
1000000
with
base
as
(
select
1
as
n
union
all
select
n
+
1
from
base
where
n
<
ceiling(sqrt(@n))
),
expand
as
(
select
1
as
c
from
base
as
b1,
base
as
b2
),
nums
as
(
select
row_number()
over(order
by
c)
as
n
from
expand
)
select
n
from
nums
where
n
<=
@n
option(maxrecursion
0)
--2
create
function
dbo.fn_nums(@n
as
bigint)
returns
table
as
return
with
l0
as(select
1
as
c
union
all
select
1),
l1
as(select
1
as
c
from
l0
as
a,
l0
as
b),
l2
as(select
1
as
c
from
l1
as
a,
l1
as
b),
l3
as(select
1
as
c
from
l2
as
a,
l2
as
b),
l4
as(select
1
as
c
from
l3
as
a,
l3
as
b),
l5
as(select
1
as
c
from
l4
as
a,
l4
as
b),
nums
as(select
row_number()
over(order
by
c)
as
n
from
l5)
select
n
from
nums
where
n
<=
@n
go
--2000
这个会比前两个慢，但是前两个2000不能用
create
table
dbo.nums(n
int
not
null
primary
key)
declare
@max
as
int,
@rc
as
int
set
@max
=
1000000
set
@rc
=
1
insert
into
nums
values(1)
while
@rc
*
2
<=
@max
begin
insert
into
dbo.nums
select
n
+
@rc
from
dbo.nums
set
@rc
=
@rc
*
2
end
insert
into
dbo.nums
select
n
+
@rc
from
dbo.nums
where
n
+
@rc
<=
@max
--------------------------------------------------------------------------------------------------------
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