回答如下:cos3x=cos(2x+x)=cos2xcosx-sin2xsinx=(2cos²x-1)cosx-2(1-cos²x)cosx=4cos³x-3cosx扩展资料:三倍角公式:sin(3α) = 3sinα-4sin3α = 4sinα·sin(60°+α)sin(60°-α)cos(3α) = 4cos3α-3cosα = 4cosα·cos(60°+α)cos(60°-α)tan(3α) = (3tanα-tan3α)/(1-3tan²α) = tanαtan(π/3+α)tan(π/3-α)cot(3α)=(cot3α-3cotα)/(3cot2α-1)
函数y=sin2x+cos3x的周期怎么求欢迎分享,转载请注明来源:内存溢出
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