【python刷题】二维数组的旋转

概述matrix=[[1,2,3,4],[5,6,7,8],[9,10,11,12]]顺序旋转deforder_rotate(matrix):res=list(zip(*matrix))res=[alist[::-1]foralistinres]returnresres1=order_rotate(matrix)print(res1)[(9,5,1),(10,6,2),(11,7,3),(12,8,4)]逆序旋

matrix = [[1,2,3,4],[5,6,7,8],[9,10,11,12]]

顺序旋转

def order_rotate(matrix):    res = List(zip(*matrix))    res = [aList[::-1] for aList in res]    return resres1 = order_rotate(matrix)print(res1)

[(9, 5, 1), (10, 6, 2), (11, 7, 3), (12, 8, 4)]

逆序旋转

def reverse_rotate(matrix):    res = List(zip(*matrix))[::-1]    return resres2 = reverse_rotate(matrix)print(res2)

[(4, 8, 12), (3, 7, 11), (2, 6, 10), (1, 5, 9)]

应用：顺序打印数组

def print_matrix(matrix):    res = []    while len(matrix) > 0:        res.extend(matrix[0])        matrix = List(zip(*matrix[1:]))[::-1]    return resres = print_matrix(matrix)print(res)

[1, 2, 3, 4, 8, 12, 11, 10, 9, 5, 6, 7]

总结

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