实际上每个元素有4个内容:名称,输入/输出,区域和日期&时间,由’〜’连接. (‘〜’可以更改.)我想将列表重组为排序顺序.
a_List = ["Chris~Check-in~Zoom A~11/13/2013 05:20","Chris~Check-in~Zoom G~11/15/2013 14:09","Frank E~Check-in~Zoom K~11/11/2013 08:48","Frank E~Check-in~Zoom K~11/15/2013 21:32","Kala Lu S~Check-in~Zoom N~11/13/2013 07:20","Milly Emily~Check-in~Zoom G~11/13/2013 01:08","Milly Emily~Check-in~Zoom E~11/16/2013 14:39","Milly Amy~Check-in~Zoom G~11/10/2013 20:14","Milly Amy~Check-in~Zoom A~11/16/2013 08:55","Milly Amy~Check-in~Zoom O~11/14/2013 21:57","Milly Amy~Check-in~Zoom A~11/15/2013 10:45","Nago Iko~Check-in~Zoom K~11/16/2013 20:42","Nago Iko~Check-in~Zoom K~11/14/2013 10:46","liz D~Check-in~Zoom N~11/15/2013 01:46","liz D~Check-in~Zoom A~11/12/2013 09:54","liz D~Check-in~Zoom G~11/16/2013 13:15","Chris~Check-out~Zoom A~11/13/2013 13:42","Chris~Check-out~Zoom G~11/11/2013 14:21","Chris~Check-out~Zoom G~11/16/2013 09:41","Frank E~Check-out~Zoom K~11/14/2013 03:02","House P~Check-out~Zoom K~11/10/2013 11:17","Kala Lu S~Check-out~Zoom G~11/11/2013 23:27","Kala Lu S~Check-out~Zoom N~11/14/2013 11:17"]
它可以导入到MS Excel并进行排序,但我想知道Python是否可以完成这项工作.
是否可以按列表中的顺序对它们进行排序:1.名称,2.日期和时间3.区域4.进/出?喜欢:
new_List = ["Chris~Check-out~Zoom G~11/08/2014 14:21","Chris~Check-in~Zoom A~11/10/2014 05:20","Chris~Check-out~Zoom A~11/10/2014 13:42","Chris~Check-in~Zoom G~11/12/2014 14:09","Chris~Check-out~Zoom G~11/13/2014 09:41","Frank E~Check-in~Zoom K~11/08/2014 08:48","Frank E~Check-out~Zoom K~11/11/2014 03:02","Frank E~Check-in~Zoom K~11/12/2014 21:32",......]
谢谢.
解决方法 您可以拆分列表,然后使用自定义键功能进行排序.但是您需要首先解析日期以正确排序它们.import datetimenew_l = sorted((x.split('~') for x in l),key=lambda x: (x[0],datetime.datetime.strptime(x[3],'%m/%d/%Y %H:%M'),x[2],x[1]))
键函数返回一个元组.元组按字典顺序进行比较;比较第一项;如果它们相同则比较第二项,依此类推
或者,您可以分阶段进行分类.这将允许您指定要按升序或降序排序的列.
from operator import itemgetternl = [x.split('~') for x in l]nl.sort(key=itemgetter(1))nl.sort(key=itemgetter(2))nl.sort(key=lambda x: datetime.datetime.strptime(x[3],reverse=True) # Newest firstnl.sort(key=itemgetter(0))
请记住,两种方式都会使新列表分割如下:
new_List = [["Chris","Check-out","Zoom G","11/08/2014 14:21"],...]
如果要将它们更改回原始表单,可以加入它们:
new_List_joined = ['~'.join(x) for x in new_List]总结
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