c – 无法将’this’指针从’const container’转换为’container&’

概述我在以下代码中遇到了STL编译错误. #include <cstdio>#include <string>template <typename T>class container {public: container(std::string in_key="") { m_element_index = 0; } ~container() { } // Retu 我在以下代码中遇到了STL编译错误.

#include <cstdio>#include <string>template <typename T>class container {public:  container(std::string in_key="") {    m_element_index = 0;  }  ~container() {  }  // Returns the numbers of elements in the container  int size() {    return m_element_index;  }  // Assignment operator  // Assigns a copy of container x as the new content for the container object.  container& operator= (const container& other) {    if (this != &other) {      for ( int IDx = 0; IDx < other.size(); IDx++) {      }    }    return *this;  }private:  int m_element_index;};int main ( int argc,char** argv) {  container<int> v1("my_container");  container<int> v2("copy_cont");  v2 = v1;}

获取以下行的错误

for(int IDx = 0; IDx< other.size(); IDx){ 错误是

1>------ Build started: Project: test,Configuration: DeBUG Win32 ------1>  test.cpp1>e:\avinash\test\test\test.cpp(20): error C2662: 'container<T>::size' : cannot convert 'this' pointer from 'const container<T>' to 'container<T> &'1>          with1>          [1>              T=int1>          ]1>          Conversion loses qualifIErs1>          e:\avinash\test\test\test.cpp(18) : while compiling class template member function 'container<T> &container<T>::operator =(const container<T> &)'1>          with1>          [1>              T=int1>          ]1>          e:\avinash\test\test\test.cpp(30) : see reference to class template instantiation 'container<T>' being compiled1>          with1>          [1>              T=int1>          ]========== Build: 0 succeeded,1 Failed,0 up-to-date,0 skipped ==========

解决方法 你需要改变这个：

int size() {    return m_element_index;  }

对此：

int size() const {    return m_element_index;  }

告诉编译器你希望它允许在const实例上调用size().

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