GitHub - jzplp/aoapc-UVA-Answer: 算法竞赛入门经典 例题和习题答案 刘汝佳 第二版
AC代码
#include
#include
#include
using namespace std;
struct point {
int x, y;
};
bool cmp1(const point &lhs, const point &rhs) {
if(lhs.x != rhs.x) {
return lhs.x < rhs.x;
}
return lhs.y < rhs.y;
}
bool cmp2(const point &lhs, const point &rhs) {
if(lhs.x != rhs.x) {
return lhs.x < rhs.x;
}
return lhs.y > rhs.y;
}
int main() {
int t, n, i, j, k, a, b;
cin >> t;
bool cut2, flag;
while(t--) {
vector v;
cin >> n;
for(i = 0; i < n; ++i) {
point p;
cin >> p.x >> p.y;
v.push_back(p);
}
sort(v.begin(), v.end(), cmp1);
int beg1 = 0, end1, beg2, end2 = n - 1, xcut;
cut2 = false;
if(n % 2 == 0) {
end1 = n/2 - 1;
beg2 = n/2;
int sum = v[beg2].x + v[end1].x;
xcut = sum / 2;
if(sum % 2 != 0) {
cut2 = true;
}
// xcut = (v[n/2].x + v[n/2 - 1].x) / 2;
} else {
xcut = v[n/2].x;
end1 = n/2 - 1;
beg2 = n/2 + 1;
}
sort(v.begin() + beg2, v.end(), cmp2);
flag = true;
for(i = beg1; i <= end1; ++i) {
a = i;
b = end2 - i;
if(v[a].x == xcut && v[b].x == xcut) {
continue;
}
if(v[a].y != v[b].y) {
flag = false;
break;
}
if(!cut2) {
if((xcut - v[a].x) != (v[b].x - xcut)) {
flag = false;
break;
}
}
if(cut2) {
if((xcut - v[a].x) != (v[b].x - xcut - 1)) {
flag = false;
break;
}
}
}
if(flag) {
cout << "YES" << endl;
} else {
cout << "NO" << endl;
}
}
return 0;
}
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