栈与字符串
只有几个用链表 *** 作的简单题目
- 实验目的(结出本次实验所涉及并要求掌握的知识点)
- 掌握栈的结构及基本运算的实现方法。
- 掌握用栈实现表达式计算的基本方法。
- 掌握用栈进行问题求解的基本方法。
- 理解掌握串的有关概念和运算实现。
- 掌握快速模式匹配等串的典型算法。
2.实验内容(结出实验内容具体描述)
1.已知顺序栈的存储结构及基本 *** 作以定义,利用顺序栈结构,编写算法函数void Dto16(unsigned int m),实现十进制无符号整数m到十六进制的转换。
2.基于下面的链式存储结构,重新实现栈的基本 *** 作,并基于链式栈,改写上题的进位转换程序。
4.利用字符串采用带头结点的链式存储结构,请编写函数node* substring(node* s,int i,int len)函数,在字符串s中从第i个位置起取长度为len的字串,函数返回字串链表
5.字符串采用带头结点的链表存储,设计算法函数void delstring(linkstring s,int i,int len)在字符串s中删除从第i个位置开始,长度为len的字串。
6.字符串采用带头结点的链表存储,编写函数linkstring index(linkstring s,linkstring t),查找字串t在主串s中第一次出现的位置,若匹配不成功,则返回NULL。
3.算法描述及实验步骤(用适当的形式表达算法设计思想与算法实现步骤)
#include //实验1
#include
#include
#include
using namespace std;
typedef struct node
{
char data;
struct node *next;
} node;
void Doto16(int m) //直接对16做除法,记录商及余数,倒序输出
{
cout << "十进制数" << m << "对应的十六进制数:";
int b;
node *top = NULL;
node *p;
while (m)
{
b = m % 16;
m /= 16;
p = new node;
if (b < 10)
b = b + '0';
else
b = b - 10 + 'A';
p->data = b;
p->next = top;
top = p;
}
while (top)
{
cout << setw(2) << top->data;
top = top->next;
}
cout << endl;
}
int main()
{
int n;
cout << "请输入待转换的十进制数" << endl;
cin >> n;
Doto16(n);
system("pause");
return 0;
}
#include //实验2
#include
#include
#include
using namespace std;
typedef struct node
{
char data;
struct node *next;
} node;
void Doto16(int m) //直接对16做除法,记录商及余数,倒序输出
{
cout << "十进制数" << m << "对应的十六进制数:";
int b;
node *top = NULL;
node *p;
while (m)
{
b = m % 16;
m /= 16;
p = new node;
if (b < 10)
b = b + '0';
else
b = b - 10 + 'A';
p->data = b;
p->next = top;
top = p;
}
while (top)
{
cout << setw(2) << top->data;
top = top->next;
}
cout << endl;
}
int main()
{
int n;
cout << "请输入待转换的十进制数" << endl;
cin >> n;
Doto16(n);
system("pause");
return 0;
}
#include //实验4
#include
#include
#include
#include
using namespace std;
typedef struct node
{
char data;
struct node *next;
} node;
node *createstr()
{
node *s = new node;
s->next = NULL;
node *p = NULL, *r = s;
char ch;
cout << "请输入#为结束符:";
cin >> ch;
while (ch != '#')
{
p = new node;
p->data = ch;
r->next = p;
r = p;
cin >> ch;
}
if (r)
r->next = NULL;
return s;
}
void output(node *s)
{
node *p = s->next;
if (!p)
{
cout << "空的" << endl;
return;
}
while (p)
{
cout << setw(4) << p->data;
p = p->next;
}
cout << endl;
}
void dellist(node *s)
{
node *p = s;
while (s)
{
s = s->next;
free(p);
p = s;
}
}
node *substring(node *s, int pos, int len) //先找到pos位置,再创新链存节点
{
node *p, *q, *r, *w;
p = s->next;
r = new node;
w = r;
int cnt = 1;
while (p && cnt < pos)
{
p = p->next;
cnt++;
}
if (!p)
{
cout << "pos太大了" << endl;
return NULL;
}
else
{
cnt = 0;
while (p && cnt < len)
{
cnt++;
q = new node;
q->data = p->data;
w->next = q;
w = q;
p = p->next;
}
}
if (cnt < len || !p)
{
cout << "len太大了" << endl;
return NULL;
}
else
{
w->next = NULL;
return r;
}
}
int main()
{
node *S;
S = createstr();
output(S);
node *str1;
int pos, len;
cout << "请输入需获取子链的起始位置:";
cin >> pos;
cout << "请输入需获取子链的起始长度:";
cin >> len;
str1 = substring(S, pos, len);
cout << "子链为:";
output(str1);
dellist(str1);
dellist(S);
system("pause");
return 0;
}
#include //实验5
#include
#include
#include
using namespace std;
typedef struct node
{
char data;
struct node *next;
} node;
node *createstr()
{
node *s = new node;
s->next = NULL;
node *p, *r = s;
char ch;
cout << "请输入#为结束符:";
cin >> ch;
while (ch != '#')
{
p = new node;
p->data = ch;
r->next = p;
r = p;
cin >> ch;
}
if (r)
r->next = NULL;
return s;
}
void output(node *s)
{
node *p = s->next;
if (!p)
{
cout << "空的" << endl;
return;
}
while (p)
{
cout << p->data << ' ';
p = p->next;
}
cout << endl;
}
void dellist(node *s)
{
node *temp = s;
node *p = s->next;
s = s->next;
free(temp);
while (s)
{
s = s->next;
free(p);
p = s;
}
}
void delstring(node *s, int pos, int len) //先找到pos位置,再利用其前驱节点改变指针指向,释放内存
{
node *p = s->next;
node *q = s;
int cnt = 1;
node *temp;
while (p && cnt < pos)
{
q = q->next;
p = p->next;
cnt++;
}
if (!p)
{
cout << "pos开始位置太大了" << endl;
return;
}
cnt = 1;
while (p && cnt < len)
{
temp = p;
p = p->next;
free(temp);
cnt++;
}
if (!p)
{
cout << "len太大了" << endl;
q->next = NULL;
return;
}
temp = p;
q->next = p->next;
free(temp);
return;
}
int main()
{
node *S;
S = createstr();
cout << "链表为:";
output(S);
int pos, len;
cout << "请输入需删除子链的起始位置:";
cin >> pos;
cout << "请输入需删除子链的起始长度:";
cin >> len;
delstring(S, pos, len);
cout << "新链为:";
output(S);
dellist(S);
system("pause");
return 0;
}
#include //实验6
#include
#include
#include
using namespace std;
typedef struct node
{
char data;
struct node *next;
} node;
node *createstr()
{
node *s = new node;
s->next = NULL;
node *p, *r = s;
char ch;
cout << "请输入#为结束符:";
cin >> ch;
while (ch != '#')
{
p = new node;
p->data = ch;
r->next = p;
r = p;
cin >> ch;
}
if (r)
r->next = NULL;
return s;
}
void output(node *s)
{
node *p = s->next;
if (!p)
{
cout << "空的" << endl;
return;
}
while (p)
{
cout << p->data << ' ';
p = p->next;
}
cout << endl;
}
void dellist(node *s)
{
node *temp = s;
node *p = s->next;
s = s->next;
free(temp);
while (s)
{
s = s->next;
free(p);
p = s;
}
}
node *index(node *s, node *t) //朴素算法匹配,即遍历主串中每一个连续的子链,看是否与其匹配
{
node *p = s->next;
node *q = t->next;
if (!q)
{
return NULL;
}
while (p)
{
int flag = 1;
node *temp = q;
node *temp1 = p;
while (temp && temp1)
{
if (temp->data != temp1->data)
{
flag = 0;
break;
}
temp = temp->next;
temp1 = temp1->next;
}
if (flag == 1)
{
break;
return p;
}
p = p->next;
}
return p;
}
int main()
{
node *s, *t;
s = createstr();
t = createstr();
cout << "主串链表为:";
output(s);
cout << "子串链表为:";
output(t);
node *p = index(s, t);
if (!p)
cout << "不匹配" << endl;
else
cout << "匹配成功,结点位置值为:" << p->data << endl;
dellist(s);
dellist(t);
system("pause");
return 0;
}
4.调试过程及运行结果(详细记录在调试过程中出现的问题及解决方法。记录实验执行的结果)
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