- 一、效果展示
- 二、游戏功能实现(详细版)
- 1.雷盘初始化
- 2.布雷
- 3.打印雷盘
- 4.排查雷
- 5.计算周围雷的个数
- 三、test.c
- 四、game.c
- 五、game.h
一、效果展示💎💎💎今天学习一个自制小游戏——扫雷小游戏
☀️☀️☀️我们可以实现纯C语言实现扫雷小游戏,效果如下
二、游戏功能实现(详细版) 1.雷盘初始化大家也可以体现下官方版本:点我即玩
void InitBoard(char board[ROWS][COLS], int rows, int cols, char set) {
int x = 0;
int y = 0;
for (x = 0; x < rows; x++) {
for (y = 0; y < cols; y++) {
board[x][y] = set;
}
}
}
2.布雷
void SetMine(char board[ROWS][COLS], int row, int col)
{
int count = EASY_COUNT;
//1~9
//1~9
while (count)
{
int x = rand() % row + 1;
int y = rand() % col + 1;
if (board[x][y] == '0')
{
board[x][y] = '1';
count--;
}
}
}
3.打印雷盘
void DisplayBoard(char board[ROWS][COLS], int row, int col) {
int i = 0;
int j = 0;
printf("------扫雷游戏------\n");
for (j = 0; j <= col; j++) {
printf("%d ", j);
}
printf("\n");
for (i = 1; i <= row; i++) {
printf("%d ", i);
for (j = 1; j <= col; j++) {
printf("%c ", board[i][j]);
}
printf("\n");
}
printf("------扫雷游戏------\n");
}
4.排查雷
void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col)
{
int x = 0;
int y = 0;
int win = 0;//找到非雷的个数
while (win < row * col - EASY_COUNT)
{
printf("请输入要排查的坐标:>");
scanf("%d%d", &x, &y);
if (x >= 1 && x <= row && y >= 1 && y <= col)
{
if (show[x][y] != '*')
{
printf("该坐标被排查过了,不能重复排查\n");
}
else
{
//如果是雷
if (mine[x][y] == '1')
{
printf("很遗憾,你被炸死了\n");
DisplayBoard(mine, ROW, COL);
break;
}
else//如果不是雷
{
win++;
//统计mine数组中x,y坐标周围有几个雷
int count = get_mine_count(mine, x, y);
show[x][y] = count + '0';//转换成数字字符
DisplayBoard(show, ROW, COL);
}
}
}
else
{
printf("输入的坐标非法,请重新输入\n");
}
}
if (win == row * col - EASY_COUNT)
{
printf("恭喜你,排雷成功\n");
DisplayBoard(mine, ROW, COL);
}
}
5.计算周围雷的个数💎💎💎这里仅仅是简单的把选择的位置点击出来,不含任何技术,如果大家感兴趣的话,可能用递归实现点击实现一大片的功能
int get_mine_count(char board[ROWS][COLS], int x, int y)
{
return (board[x - 1][y] +
board[x - 1][y - 1] +
board[x][y - 1] +
board[x + 1][y - 1] +
board[x + 1][y] +
board[x + 1][y + 1] +
board[x][y + 1] +
board[x - 1][y + 1] - 8 * '0');
}
三、test.c
#define _CRT_SECURE_NO_WARNINGS 1
#include"game.h"
void menu() {
printf("********************\n");
printf("**** 1.play ******\n");
printf("**** 0.exit ******\n");
printf("********************\n");
}
void game() {
//存放雷的信息
char mine[ROWS][COLS] = { 0 };
//存放排查出雷的信息
char show[ROWS][COLS] = { 0 };
//初始化数组内容为指定内容
//mine 数组在没有布置雷的时候都是'0'
InitBoard(mine, ROWS, COLS, '0');
//show 数组在没有布置雷的时候都是'*'
InitBoard(show, ROWS, COLS, '*');
//设置雷
SetMine(mine, ROW, COL);
DisplayBoard(show, ROW, COL);
//排查雷
FindMine(mine, show, ROW, COL);
}
int main() {
//设置随机数的起点
srand((unsigned int)time(NULL));
int input = 0;
do {
menu();
printf("请选择:>");
scanf("%d", &input);
switch (input) {
case 1:
game();
break;
case 0:
printf("退出游戏\n");
break;
default:
printf("请重新选择\n");
break;
}
} while (input);
return 0;
}
四、game.c
#define _CRT_SECURE_NO_WARNINGS 1
#include"game.h"
void InitBoard(char board[ROWS][COLS], int rows, int cols, char set) {
int x = 0;
int y = 0;
for (x = 0; x < rows; x++) {
for (y = 0; y < cols; y++) {
board[x][y] = set;
}
}
}
void DisplayBoard(char board[ROWS][COLS], int row, int col) {
int i = 0;
int j = 0;
printf("------扫雷游戏------\n");
for (j = 0; j <= col; j++) {
printf("%d ", j);
}
printf("\n");
for (i = 1; i <= row; i++) {
printf("%d ", i);
for (j = 1; j <= col; j++) {
printf("%c ", board[i][j]);
}
printf("\n");
}
printf("------扫雷游戏------\n");
}
void SetMine(char board[ROWS][COLS], int row, int col)
{
int count = EASY_COUNT;
//1~9
//1~9
while (count)
{
int x = rand() % row + 1;
int y = rand() % col + 1;
if (board[x][y] == '0')
{
board[x][y] = '1';
count--;
}
}
}
int get_mine_count(char board[ROWS][COLS], int x, int y)
{
return (board[x - 1][y] +
board[x - 1][y - 1] +
board[x][y - 1] +
board[x + 1][y - 1] +
board[x + 1][y] +
board[x + 1][y + 1] +
board[x][y + 1] +
board[x - 1][y + 1] - 8 * '0');
}
void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col)
{
int x = 0;
int y = 0;
int win = 0;//找到非雷的个数
while (win < row * col - EASY_COUNT)
{
printf("请输入要排查的坐标:>");
scanf("%d%d", &x, &y);
if (x >= 1 && x <= row && y >= 1 && y <= col)
{
if (show[x][y] != '*')
{
printf("该坐标被排查过了,不能重复排查\n");
}
else
{
//如果是雷
if (mine[x][y] == '1')
{
printf("很遗憾,你被炸死了\n");
DisplayBoard(mine, ROW, COL);
break;
}
else//如果不是雷
{
win++;
//统计mine数组中x,y坐标周围有几个雷
int count = get_mine_count(mine, x, y);
show[x][y] = count + '0';//转换成数字字符
DisplayBoard(show, ROW, COL);
}
}
}
else
{
printf("输入的坐标非法,请重新输入\n");
}
}
if (win == row * col - EASY_COUNT)
{
printf("恭喜你,排雷成功\n");
DisplayBoard(mine, ROW, COL);
}
}
五、game.h
#pragma once
#include
#include
#include
#define ROW 9
#define COL 9
#define ROWS ROW+2
#define COLS COL+2
#define EASY_COUNT 10
void InitBoard(char board[ROWS][COLS], int rows, int cols, char set);
void SetMine(char board[ROWS][COLS], int row, int col);
void DisplayBoard(char board[ROWS][COLS], int row, int col);
void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col);
欢迎分享,转载请注明来源:内存溢出
评论列表(0条)