[Swift]LeetCode434. 字符串中的单词数 | Number of Segments in a String

[Swift]LeetCode434. 字符串中的单词数 | Number of Segments in a String,第1张

概述Count the number of segments in a string, where a segment is defined to be a contiguous sequence of non-space characters. Please note that the string does not contain any non-printable characters. Exa

Count the number of segments in a string,where a segment is defined to be a contiguous sequence of non-space characters.

Please note that the string does not contain any non-printable characters.

Example:

input: "Hello,my name is John"Output: 5

统计字符串中的单词个数,这里的单词指的是连续的不是空格的字符。

请注意,你可以假定字符串里不包括任何不可打印的字符。

示例:

输入: "Hello,my name is John"输出: 5
8ms
 1 class Solution { 2     func countSegments(_ s: String) -> Int { 3         if s == nil || s.count == 0 {return 0} 4         var word:Int = 0 5         var count:Int = 0 6         //按索引遍历 7         for i in s.indices 8         { 9             if s[i] == " "10             {11                 if word > 012                 {13                     count += 114                     word = 015                 }16             }17             else18             {19                 word += 120             }            21         }22         if word > 023         {24             count += 125         }26         return count27     }28 }

8ms

 1 class Solution { 2     func countSegments(_ s: String) -> Int { 3         var count = 0 4         var segmentInProgress = false 5         for char in s { 6             if char != " " && !segmentInProgress { 7                 count += 1 8                 segmentInProgress = true 9             } else if char == " " {10                 segmentInProgress = false11             }12         }13         14         return count15     }16 }

12ms

1 class Solution {2     func countSegments(_ s: String) -> Int {3         return s.split(separator: " ").count4     }5 }

16ms

1 class Solution {2     func countSegments(_ s: String) -> Int {3         return s.characters.split(separator: " ").count4     }5 }
总结

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