ios – Xcode UI测试允许系统警报系列

概述我有问题,如果我尝试允许系列系统警报,只工作一次,下一个警报不“允许” 我在Google上搜索更多时间,并了解该帖子：( Xcode 7 UI Testing: how to dismiss a series of system alerts in code) 没什么..不行. 这是我当前的代码,首先警告“允许”成功,未检测到下一个警报.. XCUIApplication *app = [[XCU 我有问题,如果我尝试允许系列系统警报,只工作一次,下一个警报不“允许”
我在Google上搜索更多时间,并了解该帖子：( Xcode 7 UI Testing: how to dismiss a series of system alerts in code)
没什么..不行.
这是我当前的代码,首先警告“允许”成功,未检测到下一个警报..

XCUIApplication *app = [[XCUIApplication alloc] init];app.launchEnvironment = @{        @"isUITest" : @YES,@"withFakeData" : fakeData};[app launch];for (int i = 1; i <= self.possibleSystemAlerts; i++) {    NSLog(@"%d",i);    XCTestExpectation *expectation = [self expectationWithDescription:@"High Expectations"];    ID monitor = [self addUIInterruptionMonitorWithDescription:@"Push notifications" handler:^BOol(XCUIElement *_Nonnull interruptingElement) {        XCUIElement *element = interruptingElement;        XCUIElement *allow = element.buttons[@"Allow"];        XCUIElement *ok = element.buttons[@"OK"];        if ([ok exists]) {            [ok tap];            [expectation fulfill];            return YES;        }        if ([allow exists]) {            [allow forceTap];            [expectation fulfill];            return YES;        }        return NO;    }];    [app tap];    [self waitForExpectationsWithTimeout:6.0 handler:^(NSError *error) {        if (error) {            NSLog(@"Timeout Error: %@",error);        }    }];    [self removeUIInterruptionMonitor:monitor];}

最好的祝福,
伊万.

UPD：

好的,我找到了解决方案,如何在第一次提醒后,尝试关闭第二个(感谢这个网站：http://www.it1me.com/it-answers?id=32148965&s=Template:Viper&ttl=Xcode+7+UI+Testing%3A+how+to+dismiss+a+series+of+system+alerts+in+code)只需要返回总是没有.

但另一个问题……

t =    10.18s                     Find: Descendants matching type Alert    t =    10.18s                     Find: IDentity Binding    t =    11.19s                     Find the "Allow “MyApp” to access your location while you use the app?" Alert (retry 1)    t =    11.19s                         Snapshot accessibility hIErarchy for com.apple.springboard    t =    11.26s                         Find: Descendants matching type Alert    t =    11.26s                         Find: IDentity Binding    t =    12.27s                     Find the "Allow “MyApp” to access your location while you use the app?" Alert (retry 2)    t =    12.27s                         Snapshot accessibility hIErarchy for com.apple.springboard    t =    12.33s                         Find: Descendants matching type Alert    t =    12.34s                         Find: IDentity Binding    t =    12.42s                     Assertion Failure: UI Testing Failure - No matches found for "Allow “MyApp” to access your location while you use the app?" Alertquery input was {(    Alert 0x7febe8731630: traits: 72057602627862528,{{25.0,193.0},{270.0,182.0}},label: '“MyApp” Would like to Send You Notifications')}

他尝试关闭第三个通知,而不是第二个,当然他没有找到这个系统警报……

解决方法 在应用启动之前逐个创建警报处理程序.此外,在与警报交互之前,请务必在应用上的任意位置点按().这是Xcode中的已知错误.

addUIInterruptionMonitor(withDescription:"First Dialog") { (alert) -> Bool in    alert.buttons["Allow"].tap()    return true}addUIInterruptionMonitor(withDescription:"Second Dialog") { (alert) -> Bool in    alert.buttons["Allow"].tap()    return true}addUIInterruptionMonitor(withDescription:"Third Dialog") { (alert) -> Bool in    alert.buttons["Allow"].tap()    return true}let app = XCUIApplication()app.launch()app.tap()app.tap()app.tap()

这三个水龙头将连续启动每个警报处理程序,而不会实际触发您的应用程序中的任何事件.另请注意,每个中断处理程序都不会指定有关警报的任何内容,只会指定确认按钮.

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