你如何测试函数和闭包的平等？

概述The book says that “functions and closures are reference types”.那么，你怎么知道参考是否相等？ ==和===不工作。 func a() { }let å = alet b = å === å // Could not find an overload for === that accepts the supplied argume The book says that “functions and closures are reference types”.那么，你怎么知道参考是否相等？ ==和===不工作。

func a() { }let å = alet b = å === å // Could not find an overload for === that accepts the supplIEd arguments

这里是Catterwauls如何处理这个：

MultiClosures & Equatable Closures

tests

Chris Lattner在开发者论坛上写道：

This is a feature we intentionally do not want to support. There are
a varIEty of things that will cause pointer equality of functions (in
the swift type system sense,which includes several kinds of closures)
to fail or change depending on optimization. If “===” were defined on
functions,the compiler would not be allowed to merge IDentical method
bodIEs,share thunks,and perform certain capture optimizations in
closures. Further,equality of this sort would be extremely
surprising in some generics contexts,where you can get reabstraction
thunks that adjust the actual signature of a function to the one the
function type expects.

https://devforums.apple.com/message/1035180#1035180

这意味着你不应该尝试比较闭包的相等性，因为优化可能会影响结果。

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