ios – 查找iphone中两个日期之间的总天数

概述我想找到两个日期之间的总天数. 例如今天是01-01-2011(DD-MM-YYYY),第二个日期是(25-03-2011),我怎样才能找到总天数？ NSDate *currentdate=[NSDate date];NSLog(@"curretdate is ==%@",currentdate);NSDateFormatter *tempFormatter1 = [[[NSDateForma 我想找到两个日期之间的总天数.

例如今天是01-01-2011(DD-MM-YYYY),第二个日期是(25-03-2011),我怎样才能找到总天数？

NSDate *currentdate=[NSDate date];NSLog(@"curretdate is ==%@",currentdate);NSDateFormatter *tempformatter1 = [[[NSDateFormatter alloc]init]autorelease];[tempformatter1 setDateFormat:@"dd-mm-YYYY hh:mm:ss"];NSDate *toDate = [tempformatter1 dateFromString:@"20-04-2011 09:00:00"];NSLog(@"toDate ==%@",toDate);

解决方法 在你的日期格式你设置错误它是dd-MM-yyyy HH：mm：ss.可能是那个问题..你得到错误的日期而没有得到答案我发送litte位代码获得一天的差异.

NSDateFormatter *tempformatter = [[[NSDateFormatter alloc]init]autorelease]; [tempformatter setDateFormat:@"dd-MM-yyyy HH:mm:ss"];  NSDate *startdate = [tempformatter dateFromString:@"15-01-2011 09:00:00"];  NSLog(@"startdate ==%@",startdate);  NSDateFormatter *tempformatter1 = [[[NSDateFormatter alloc]init]autorelease];  [tempformatter1 setDateFormat:@"dd-MM-yyyy HH:mm:ss"];  NSDate *toDate = [tempformatter1 dateFromString:@"20-01-2011 09:00:00"];  NSLog(@"toDate ==%@",toDate);   int i = [startdate timeIntervalSince1970];   int j = [toDate timeIntervalSince1970];   double X = j-i;   int days=(int)((double)X/(3600.0*24.00));   NSLog(@"Total Days Between::%d",days);

编辑1：

我们可以使用以下功能找到日期差异：

-(int)dateDiffrenceFromDate:(Nsstring *)date1 second:(Nsstring *)date2 {    // Manage Date Formation same for both dates    NSDateFormatter *formatter = [[NSDateFormatter alloc] init];    [formatter setDateFormat:@"dd-MM-yyyy"];    NSDate *startDate = [formatter dateFromString:date1];    NSDate *endDate = [formatter dateFromString:date2];    unsigned flags = NSDayCalendarUnit;    NSDateComponents *difference = [[NSCalendar currentCalendar] components:flags fromDate:startDate toDate:endDate options:0];    int dayDiff = [difference day];    return dayDiff;}

来自Abizern的ans.找到更多NSDateComponent here.的信息

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