android – 如何压缩视频并上传到服务器？

概述参见英文答案 > Compress Videos using FFMPEG and JNI                                    1个 我是Android开发的新手,我无法将视频压缩到Android应用程序中. 所以,请帮我以编程方式压缩视频并上传到服务器. 我使用FFmpeg但不知道如何正确使用它.请指导我这样做. 客户端(ANDROID)代码 package p 参见英文答案 > Compress Videos using FFMPEG and JNI                                    1个
我是AndroID开发的新手,我无法将视频压缩到AndroID应用程序中.

所以,请帮我以编程方式压缩视频并上传到服务器.

我使用FFmpeg但不知道如何正确使用它.请指导我这样做.

解决方法 客户端(ANDROID)代码

package pack.coderzheaven;import java.io.DatainputStream;import java.io.DataOutputStream;import java.io.file;import java.io.fileinputStream;import java.io.IOException;import java.net.httpURLConnection;import java.net.MalformedURLException;import java.net.URL;import java.util.HashMap;import androID.app.Activity;import androID.content.Intent;import androID.database.Cursor;import androID.net.Uri;import androID.os.Bundle;import androID.os.Environment;import androID.provIDer.MediaStore;import androID.util.Log;public class UploadAudioDemo extends Activity {    private static final int SELECT_AUdio = 2;    String selectedpath = "";    @OverrIDe    public voID onCreate(Bundle savedInstanceState) {        super.onCreate(savedInstanceState);        setContentVIEw(R.layout.main);        opengalleryAudio();    }    public voID opengalleryAudio(){    Intent intent = new Intent();        intent.setType("audio/*");        intent.setAction(Intent.ACTION_GET_CONTENT);        startActivityForResult(Intent.createChooser(intent,"Select Audio "),SELECT_AUdio);   }    public voID onActivityResult(int requestCode,int resultCode,Intent data) {        if (resultCode == RESulT_OK) {            if (requestCode == SELECT_AUdio)            {                System.out.println("SELECT_AUdio");                Uri selectedImageUri = data.getData();                selectedpath = getPath(selectedImageUri);                System.out.println("SELECT_AUdio Path : " + selectedpath);                dofileUpload();            }        }    }    public String getPath(Uri uri) {        String[] projection = { MediaStore.Images.Media.DATA };        Cursor cursor = managedquery(uri,projection,null,null);        int column_index = cursor.getColumnIndexOrThrow(MediaStore.Images.Media.DATA);        cursor.movetoFirst();        return cursor.getString(column_index);    }    private voID dofileUpload(){        httpURLConnection conn = null;        DataOutputStream dos = null;        DatainputStream inStream = null;        String lineEnd = "rn";        String twoHyphens = "--";        String boundary =  "*****";        int bytesRead,bytesAvailable,bufferSize;        byte[] buffer;        int maxBufferSize = 1*1024*1024;        String responseFromServer = "";        String urlString = "http://your_website.com/upload_audio_test/upload_audio.PHP";        try        {         //------------------ CLIENT REQUEST        fileinputStream fileinputStream = new fileinputStream(new file(selectedpath) );         // open a URL connection to the Servlet         URL url = new URL(urlString);         // Open a http connection to the URL         conn = (httpURLConnection) url.openConnection();         // Allow inputs         conn.setDoinput(true);         // Allow Outputs         conn.setDoOutput(true);         // Don't use a cached copy.         conn.setUseCaches(false);         // Use a post method.         conn.setRequestMethod("POST");         conn.setRequestProperty("Connection","Keep-Alive");         conn.setRequestProperty("Content-Type","multipart/form-data;boundary="+boundary);         dos = new DataOutputStream( conn.getoutputStream() );         dos.writeBytes(twoHyphens + boundary + lineEnd);         dos.writeBytes("Content-disposition: form-data; name="uploadedfile";filename="" + selectedpath + """ + lineEnd);         dos.writeBytes(lineEnd);         // create a buffer of maximum size         bytesAvailable = fileinputStream.available();         bufferSize = Math.min(bytesAvailable,maxBufferSize);         buffer = new byte[bufferSize];         // read file and write it into form...         bytesRead = fileinputStream.read(buffer,bufferSize);         while (bytesRead > 0)         {          dos.write(buffer,bufferSize);          bytesAvailable = fileinputStream.available();          bufferSize = Math.min(bytesAvailable,maxBufferSize);          bytesRead = fileinputStream.read(buffer,bufferSize);         }         // send multipart form data necesssary after file data...         dos.writeBytes(lineEnd);         dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);         // close streams         Log.e("DeBUG","file is written");         fileinputStream.close();         dos.flush();         dos.close();        }        catch (MalformedURLException ex)        {             Log.e("DeBUG","error: " + ex.getMessage(),ex);        }        catch (IOException ioe)        {             Log.e("DeBUG","error: " + ioe.getMessage(),ioe);        }        //------------------ read the SERVER RESPONSE        try {              inStream = new DatainputStream ( conn.getinputStream() );              String str;              while (( str = inStream.readline()) != null)              {                   Log.e("DeBUG","Server Response "+str);              }              inStream.close();        }        catch (IOException ioex){             Log.e("DeBUG","error: " + ioex.getMessage(),ioex);        }      }}

服务器端(PHP)代码

<?PHP// Where the file is going to be placed$target_path = "uploads/";/* Add the original filename to our target path.Result is "uploads/filename.extension" */$target_path = $target_path . basename( $_fileS['uploadedfile']['name']);if(move_uploaded_file($_fileS['uploadedfile']['tmp_name'],$target_path)) {    echo "The file ".  basename( $_fileS['uploadedfile']['name']).    " has been uploaded";} else{    echo "There was an error uploading the file,please try again!";    echo "filename: " .  basename( $_fileS['uploadedfile']['name']);    echo "target_path: " .$target_path;}?>

要记住的事情
 1.确保您的服务器正在运行.
 2.您的服务器文件路径应该是正确的.
 3.检查服务器中的文件夹写入权限.

客户端代码上面是AUdio文件

你也可以将它用于图像,视频
通过做一些改变就好

intent.setType("audio/*");

根据您的要求使用视频/图像并使用它

用于压缩使用低于逻辑

我偶然发现的一个主要烦人的问题是我无法使用Intent向Google Mail应用发送多个附件.最快的方法当然是将所有文件压缩成一个(ZIP).

在网上搜索之后,我对你的AndroID设备上的压缩文件并没有太多了解 – 大多数文章都是针对标准的java应用程序,它假设你的所有文件都在你想要压缩的当前目录中.

所以,我尽我所能并掀起了我自己的包装类,它允许你轻松地在AndroID中压缩文件！

这是班级：

import androID.util.Log; import java.io.BufferedinputStream; import java.io.bufferedoutputstream; import java.io.fileinputStream; import java.io.fileOutputStream; import java.util.zip.ZipEntry; import java.util.zip.ZipOutputStream; public class Compress {   private static final int BUFFER = 2048;   private String[] _files;   private String _zipfile;   public Compress(String[] files,String zipfile) {     _files = files;     _zipfile = zipfile;   }   public voID zip() {     try  {       BufferedinputStream origin = null;       fileOutputStream dest = new fileOutputStream(_zipfile);       ZipOutputStream out = new ZipOutputStream(new bufferedoutputstream(dest));       byte data[] = new byte[BUFFER];       for(int i=0; i < _files.length; i++) {         Log.v("Compress","Adding: " + _files[i]);         fileinputStream fi = new fileinputStream(_files[i]);         origin = new BufferedinputStream(fi,BUFFER);         ZipEntry entry = new ZipEntry(_files[i].substring(_files[i].lastIndexOf("/") + 1));         out.putNextEntry(entry);         int count;         while ((count = origin.read(data,BUFFER)) != -1) {           out.write(data,count);         }         origin.close();       }       out.close();     } catch(Exception e) {       e.printstacktrace();     }   } }

如果这一切对你都有意义,那么你可能不会对我的解释感兴趣,否则,继续阅读. 总结

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