void main()
{
float i,j
char ch
printf("*************************************\n")
printf("** This is a arithmetic calculator:**\n")
printf("*************************************\n")
while(1)
{ printf("input i,j:")
scanf("%f%f",&i,&j)
printf("input op:")
ch=getche()
printf("\n")
switch(ch)
{
case'+':
printf("%.4f+%.4f=%.4f\n",i,j,i+j)break
case'-':
printf("%.4f-%.4f=%.4f\n",i,j,i-j)break
case'*':
printf("%.4f*%.4f=%.4f\n",i,j,i*j)break
case'/':
{
if(j==0)
{
printf("error")
while(j>0)
{
printf("input i,j:")
scanf("%.4f%.4f",&i,&j)
}
}
else printf("%.4f/%.4f=%.4f\n",i,j,i/j)
break
}
}
}
}
你说的是 vc 还是 tc 啊???其他的运算:
#include <stdio.h>
int add(int x,int y) {return x+y}
int sub(int x,int y) {return x-y}
int mul(int x,int y) {return x*y}
int div(int x,int y) {return x/y}
int (*func[])()={add,sub,mul,div}
int num,curch
char chtbl[]="+-*/()="
char corch[]="+-*/()=0123456789"
int getach() {
int i
while(1) {
curch=getchar()
if(curch==EOF) return -1
for(i=0corch[i]&&curch!=corch[i]i++)
if(i<strlen(corch)) break
}
return curch
}
int getid() {
int i
if(curch>='0'&&curch<='9') {
for(num=0curch>='0'&&curch<='9'getach())num=10*num+curch-'0'
return -1
}
else {
for(i=0chtbl[i]i++) if(chtbl[i]==curch) break
if(i<=5) getach()
return i
}
}
int cal() {
int x1,x2,x3,op1,op2,i
i=getid()
if(i==4)x1=cal() else x1=num
op1=getid()
if(op1>=5) return x1
i=getid()
if(i==4) x2=cal() else x2=num
op2=getid()
while(op2<=4) {
i=getid()
if(i==4) x3=cal() else x3=num
if((op1/2==0)&&(op2/2==1))x2=(*func[op2])(x2,x3)
else {
x1=(*func[op1])(x1,x2)
x2=x3
op1=op2
}
op2=getid()
}
return (*func[op1])(x1,x2)
}
void main(void) {
int value
printf("Please input an expression:\n")
getach()
while(curch!='=') {
value=cal()
printf("The result is:%d\n",value)
printf("Please input an expression:\n")
getach()
}
}
只能 + - * /
class Program{
static void Main(string[] args)
{
calculator a = new calculator()
a.ADD(1, 2)
a.Minus(2, 1)
a.Multiply(2, 2)
a.Except(2, 2)
}
public class calculator
{
public int ADD(int a, int b)
{
return a + b
}
public int Minus(int a, int b)
{
return a - b
}
public int Multiply(int a, int b)
{
return a * b
}
public int Except(int a, int b)
{
return a / b
}
}
}
欢迎分享,转载请注明来源:内存溢出
评论列表(0条)