设计一个斗地主游戏,该如何设计各种类?(面向对象,设计模式相关)

先设计类啦，类的内部在嵌套一个牌类，牌类的成员无非就那几个:花色、大小、名称

类有那些判断牌类型的函数，比如判断是对子，三代，联队，连子，飞机，炸d。。。。。。

你要压过别人的牌，就首先得判断牌类型，函数已经定义好了，还得判断你的牌是否打过对方，这又需要函数来解决，具体思路你按自己打牌的规矩来设计呗

希望采纳

这是以随机的形式发牌的。希望能帮到你。

int main(){int a[60] int b[60] int w = 0 int wi,wj,wii int i,j,index,x=0,m for(i=0i<54i++)a[i]=i+1 srand((unsigned)time(0)) for(i=0i<54){index=rand()%54 if(a[index]!=0){b[i]=a[index] //printf("%d ",b[i]) a[index]=0 ++i }}printf("\n说明：\n") printf("*******************\n") printf("**红桃 %c ",3) printf("**\n") printf("**方块 %c ",4) printf("**\n") printf("**梅花 %c ",5) printf("**\n") printf("**黑桃 %c ",6) printf("**\n") printf("**大王 A **\n**小王 a **\n") printf("*******************\n") printf("\n请输入打牌人数：\n") scanf("%d",&w) wi = 54/w wj = 54%w //printf("%d,%d",wi,wj) for (j = 0j <wj++){m = 0 printf("\n\n第%d个人的牌\n",j+1) wj -- if (wj>=0)wii = wi + 1 elsewii = wi//红桃printf("红桃 %c ",3) printf(":") for(i = j*wiii<(j+1)*wiii++){if (b[i]<=13&&b[i]>0){m++ if (b[i]==11)printf("J ") else if (b[i]==12)printf("Q ") else if (b[i]==13)printf("K ") elseprintf("%d ",b[i]) }} //方块printf("\n方块 %c ",4) printf(":") for(i = j*wiii<(j+1)*wiii++){if (b[i]<=26&&b[i]>13){m++ b[i] = b[i]-13 if (b[i]==11)printf("J ") else if (b[i]==12)printf("Q ") else if (b[i]==13)printf("K ") elseprintf("%d ",b[i]) }} //梅花printf("\n梅花 %c ",5) printf(":") for(i = j*wiii<(j+1)*wiii++){ if (b[i]<=39&&b[i]>26){m++ b[i] = b[i]-26 if (b[i]==11)printf("J ") else if (b[i]==12)printf("Q ") else if (b[i]==13)printf("K ") elseprintf("%d ",b[i]) }}//黑桃printf("\n黑桃 %c ",6) printf(":") for(i = j*wiii<(j+1)*wiii++){if (b[i]<=52&&b[i]>39){m++ b[i] = b[i]-39 if (b[i]==11)printf("J ") else if (b[i]==12)printf("Q ") else if (b[i]==13)printf("K ") elseprintf("%d ",b[i]) }}//大小王printf("\n大小王 A or a :") for(i = j*wiii<=(j+1)*wiii++){if (b[i]==53){m++ printf("A ") }if (b[i]==54){m++ printf("a ") }}printf("\n总共：%d张牌！！！",m) } }

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