java拼字游戏（1组10个字母中至少2个原音字母，可重复字母）拼对得分 拼错换人..

import java.io.BufferedReader

import java.io.FileReader

import java.io.IOException

import java.util.ArrayList

import java.util.Random

import java.util.Scanner

public class Words {

private static char[] consonant={'B','C','D','F','G','H','J','K','L','M','N','P','Q',

'R','S','T','V','W','X','Y','Z'}

private static char[] vowel={'A','E','I','O','U'}

private static ArrayList<String>dict = new ArrayList<String>()

public static void main(String[] args) throws IOException {

// TODO Auto-generated method stub

getResource()

int score1 = 0

int score2 = 0

Scanner userInput = new Scanner(System.in)

String A= null

int count = 0

boolean flag = false//true 为Player1, FALSE为Player2

do{

String random = randomString()

System.out.println(random)

if(flag)

{

System.out.println("Player1 input a word: (or ‘@’ to pass or ‘!’ to quit)")

A=userInput.nextLine()

if(A.equals("@") )

{

flag =!flag

System.out.println("Player2 input a word: (or ‘@’ to pass or ‘!’ to quit)")

A =userInput.nextLine()

}

}

else

{

System.out.println("Player2 input a word: (or ‘@’ to pass or ‘!’ to quit)")

A=userInput.nextLine()

if(A.equals("@") )

{

flag = !flag

System.out.println("Player1 input a word: (or ‘@’ to pass or ‘!’ to quit)")

A =userInput.nextLine()

}

}

if(A.equals("@"))

{

System.out.println("反复切换，系统退出")

return

}

else

{

String temp = null

if(flag)

{

//String random = randomString()

temp = match(random,A)

if(find(temp,dict))

score1+=2

System.out.println(" Player1 get "+score1+" points")

}

else

{

//String random = randomString()

temp = match(random,A)

if(find(temp,dict))

score2+=2

System.out.println(" Player2 get "+score2+" points")

}

}

count++

}while(count <10&&(!A.equals("!")))

System.out.println("游戏结束！")

System.out.println("Player1 get"+score1+"points")

System.out.println("Player2 get"+score2+"points")

if(A.equals("!") )

System.out.println("exit")

}

public static String randomString()//产生随机字符串

{

Random generator = new Random()

String temp = new String()

for(int i = 0i<8i++)

temp += consonant[generator.nextInt(20)+1]

temp+=vowel[generator.nextInt(4)+1]

temp+=vowel[generator.nextInt(4)+1]

return temp

}

public static String match(String str1,String str2)//

{

if(str1.contains(str2))

{

System.out.println("Bingo,you get it!")

return str2

}

else

{

String temp = new String()

L1: for(int i = 0i<str2.length()i++)

{

for(int j = 0j<str1.length()j++)

if(str2.charAt(i)==str1.charAt(j))

{

temp += str2.charAt(i)

continue L1

}

}

return temp

}

}

public static boolean find(String str,ArrayList<String>soure)//从读取的信息中查找输入的字符串

{

for(int i = 0i <soure.size()i++)

{

if(soure.get(i).equals(str))

{

System.out.println("Find It ! You can get two points")

return true

}

}

return false

}

public static void getResource() throws IOException//读取words.txt文件

{

FileReader fin = new FileReader("words.txt")

BufferedReader bin = new BufferedReader(fin)

String str = null

do{

str = bin.readLine()

if(str!=null)

dict.add(str)

}while(str!=null)

bin.close()

fin.close()

}

}

*

* java程序编写：有100匹马，驮100担货，大马驮3担，中马驮2担，两匹小马驮1担，问有大、中、小马各多少？

*

* 编程思路：

*

* 假设： 大马 x个 中马 y 个 小马 (100-x-y) 个

* 那么 3*x + 2*y + (100-x-y)/2 = 100

*

* 并且 x>=0 y>=0 (100-x-y)>=0[即 x+y<=100]

* 另外 两匹小马驮1担， 说明 小马必须是双数

*

* 列出所有可能性并输出 多有满足条件的情况即可

* */

public class Demo

{

public static void main(String [] args)

{

getResult()

}

private static void getResult()

{

int count = 0

System.out.println("满足条件的情况有：")

for (int x = 0x<=100x++)

{

for(int y = 0y<=100y++)

{

int z = 100-x-y

if( z%2==0&&3*x + 2*y + z/2 == 100)

{

count++

System.out.println("情况"+count+":大马"+x+"个，"+"中马"+y+"个"+"，小马"+z+"个")

}

}

}

}

}