//4*4键盘检测程序,按下键后相应的代码显示在数码管上
#include<reg51.h>
sbit beep=P2^3
sbit dula=P2^6
sbit wela=P2^7
unsigned char i=100
unsigned char j,k,temp,key
void delay(unsigned char i)
{
for(j=ij>0j--)
for(k=125k>0k--)
}
unsigned char code table[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,
0x07,0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71}
display(unsigned char num)
{
P0=table[num]
dula=1
dula=0
P0=0xc0
wela=1
wela=0
}
void main()
{
dula=0
wela=0
while(1)
{
P3=0xfe
temp=P3
temp=temp&0xf0兄腊册
if(temp!=0xf0)
{
delay(10)
if(temp!=0xf0)
{
temp=P3
switch(temp)
{
case 0xee:
key=0
break
case 0xde:
key=1
break
case 0xbe:
key=2
break
case 0x7e:
key=3
break
}
while(temp!=0xf0)
{
temp=P3
temp=temp&0xf0
beep=0
}
beep=1
display(key)
P1=0xfe
}
}
P3=0xfd
temp=P3
temp=temp&0xf0
if(temp!=0xf0)
{
delay(10)
if(temp!=0xf0)
{
temp=P3
switch(temp)
{
case 0xed:
key=4
break
case 0xdd:
key=5
break
case 0xbd:
key=6
break
case 0x7d:
key=7
break
}
while(temp!=0xf0)
{
temp=P3
temp=temp&0xf0羡宏
beep=0
}
beep=1
display(key)
}
}
P3=0xfb
temp=P3
temp=temp&0xf0
if(temp!=0xf0)
{
delay(10)
if(temp!=0xf0)
{
temp=P3
switch(temp)
{
case 0xeb:
key=8
break
case 0xdb:
key=9
break
case 0xbb:
key=10
break
case 0x7b:
key=11
break
}
while(temp!=0xf0)
{
temp=P3
temp=temp&0xf0
beep=0
}
beep=1
display(key)
}
}
P3=0xf7
temp=P3
temp=temp&0xf0
if(temp!=0xf0)
{
delay(10)
if(temp!=0xf0)
{
temp=P3
switch(temp)
{
case 0xe7:
key=12
break
case 0xd7:
key=13
break
case 0xb7:
key=14
break
case 0x77:
key=15
break
}
while(temp!=0xf0)
{
temp=P3
temp=temp&0xf0
beep=0
}
beep=1
display(key)
}
}
}
}
帮你写了一个如下:
#include <stdio.h>#include <stdlib.h>
int main()
{
int a[4][4]
冲升int i,j
int sum1=0,sum2=0
printf("产生的4*4随机数组如下:\n")
for(i=0i<4i++)
{
for(j=0j<4j++)
{
a[i][j]=rand()%100
printf("%d\t"差判指,a[i][j])
}
printf("\n")
}
for(i=0i<4i++)
{
for(j=0j<4j++)
虚配{
if(i==j)
sum1 += a[i][j]
if(i+j == 3)
sum2 += a[i][j]
}
}
printf("左上角到右下角的对角线之和为:%d\n",sum1)
printf("右上角到左下角的对角线之和为:%d\n",sum2)
return 0
}
运行结果如下：
#include <stdio.h>void main()
{
int a[4][4],s1=0,s2=0
int i,j
for (i=0i<4i++)
for (j=0j<4j++)
scanf("%d",&a[i][j])
for (i=0,j=0i<4,j<4i++,j++)
s1=s1+a[i][j]
for (i=0,j=3i<4,j>=0i++,j--)
s2=s2+a[i][j]
printf("主对角线：宽悉%d \n副对角岩激线粗巧袜：%d\n",s1,s2)
}
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