C语言程序设计：奖金利润提成

#include<stdio.h>

#define MIN(a,b) ((a)<(b)?(a):(b))

int main()

{float lr,jj

scanf("%f",&lr)

jj=0.1*MIN(lr,100000)

if(lr>100000)jj+=0.075*MIN(lr-100000,100000)

if(lr>200000)jj+=0.05*MIN(lr-200000,200000)

if(lr>400000)jj+=0.03*MIN(lr-400000,200000)

if(lr>伍启悉600000)jj+=0.015*MIN(lr-600000,400000)

if(lr>旁消1000000)jj+=0.05*(lr-1000000)

printf("腔乎%g\n",jj)

return 0

}

代旅老亮码如下，望采纳拆宽！

#include<iostream>

#include <vector>

#include <algorithm>

using namespace std

int main()

{

int n

vector<int>x, y

int z[100]

int num = 0,num1 = 0

cout <<"提示：输入的数组用空格间隔，回车结束输入！" <<endl

cout <<"请输入天数："<<endl

cin >含游>n

cout <<"请输入每天的收入："<<endl

while (cin >>num)

{

x.push_back(num)

// 遇到回车符退出

if ( '\n' == cin.get()) break

}

cout <<"请输入每天的支出："<<endl

while (cin >>num1)

{

y.push_back(num1)

// 遇到回车符退出

if ( '\n' == cin.get()) break

}

for(int i = 0i <ni++)

z[i] = x[i] - y[i]//计算利润

sort(z, z + n)

cout <<"结果:" <<endl

int i,j,count = 0

for (i = 0i<ni=j)

{

for (j=ij<nj++)

{

if (z[i]==z[j])

{

count++

if (j == n-1)

{

cout<<z[i]<<" "<<count <<endl

}

}

else

{

cout<<z[i] <<" "<<count <<endl

count = 0

break

}

}

}

system("pause")

return 0

}

结果如下：

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