求"掷色子"的C语言算法,或代码...

是“掷骰子”吧？！！这是掷骰子的程序：题目是这样子的：编写一个模拟掷骰子的程序，每个骰子从1-6，所以两个骰子组合运州数从2-12，随机投掷10000次，打印所有组合出现的概率！

#include<iostream.h>

#include<乱悄滚time.h>

#include<stdlib.h>

void

main()

{

int

i=0

float

a[13]={0}

srand((unsigned)time(null))

int

num1=0,num2=0

for(i=1i<=10000i++)

{

num1=rand()%6+1

num2=rand()%6+1

a[num1+num2]++

a[0]++

}

for(i=2i<=12i++)

{

cout<<i<<'

'<哗余<'

'

cout<<(a[i]/a[0])*100<<'%'

cout<<endl

}

}

# -*- coding: UTF-8 -*-

import random,time

def randstr(x):

num=int(random.uniform(1,7))

return [num,"第" + str(x) + "个骰子摇出来的点如掘穗数是：" + str(num) + "\n"]

def tous(r):

sum,constr=0,""

# range(r) means 0 to r so use below

for i in range(1,r+1):

conresult=randstr(i)

sum+=conresult[0]

constr+=conresult[1]

return [sum,constr]

def calltous(k,v):

daxiao=("点数为小","点数为大渣卜")

result=tous(k)

print result[1] + "所有骰子摇得的总数是：" + str(result[0]) + "\n" + daxiao[(result[0]-v)>0] + "散帆\n"

while True:

calltous(3,10)

time.sleep(1.3)

---