用shell程序打印九九乘法表？

#!/bin/bash

for (( i=1i<=9i++ ))

do

for (( j=1j<=9j++ ))

do

[ $j -le $i ] && echo -n "${i}*${j}=$((i*j)) "#判谨弯断j是否小于i，当j大于i时不输出樱培，输出不换行，末尾加一脊晌唯个制表符

done

echo "" #输出一个换行符

done

#!/嫌祥李芹迟宴闷bin/bash

for var1 in {00..99}

do

useradd student$var1

touch /home/student$var1/aa.txt

done

#!/拍搜戚纤bin/bash

j=0

for ((i=1i<袭仔历=100i++))

do

j=$[$i+$j]

done

echo $j

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