我还真有个 这是个VC版的 网上让基找的 我只是搬运工 Linux版本的有点麻烦，用的ncurse。如果要的话我再给
#include <stdio.h>#include <stdlib.h>
#include <time.h>
#include <conio.h>
#include <string.h>
int MAP[4][4],gre
int add(int n)
{
int num = rand()
int tf = num % 2
int x,y,i
x = num % 4
srand((unsigned int)time(0))
srand((unsigned int)time(0) + (unsigned int)num)
y = rand()
y %= 4
if (tf)
num = 2
else
num = 4
if (n == 0)
{
MAP[x][y] = num
}
else if (n == 1)
{
if (MAP[3][y] == 0)
MAP[3][y] = num
else
for (i = 0 i < 4 i++)
if (MAP[3][i] == 0)
{
MAP[3][i] = num
break
}
}
else if (n == 2)
{
if (MAP[0][y] == 0)
MAP[0][y] = num
else
for (i = 0 i < 4 i++)
if (MAP[0][i] == 0)
{
MAP[0][i] 仿滑斗= num
break
}
}
else if (n == 3)
{
if (MAP[x][3] == 0)
MAP[x][3] = num
else
for (i = 0 i < 4 i++)
if (MAP[i][3] == 0)
{
MAP[i][3] = num
break
}
}
else if (n == 4)
{
if (MAP[x][0] == 0)
MAP[x][0] = num
else
for (i = 0 i < 4 i++)
if (MAP[i][0] == 0)
{
MAP[i][0] = num
break
}
}
}
int movup(void)
{
int i,k,t
int tf = 0
for (k = 0 k < 4 k++)
{
int n = 4
while (n--)
for (i = 0 i < 3 i++)
if (MAP[i][k] == 0)
{
for (t = i t < 3 t++)
{
MAP[t][k] = MAP[t + 1][k]
MAP[t + 1][k] = 0
tf = 1
}
}
for (i 备磨= 0 i < 3 i++)
{
if (MAP[i][k] == MAP[i + 1][k])
{
MAP[i][k] *= 2
gre += MAP[i][k]
if (MAP[i][k] == 2048)
return 0
for (t = i + 1 t < 3 t++)
{
MAP[t][k] = MAP[t + 1][k]
MAP[t + 1][k] = 0
tf = 1
}
}
}
}
if (tf)
add(1)
return 1
}
int movdow(void)
{
int i,k,t
int tf = 0
for (k = 0 k < 4 k++)
{
int n = 4
while (n--)
for (i = 3 i > 0 i--)
if (MAP[i][k] == 0)
{
for (t = i t > 0 t--)
{
MAP[t][k] = MAP[t - 1][k]
MAP[t - 1][k] = 0
tf = 1
}
}
for (i = 3 i > 0 i--)
{
if (MAP[i][k] == MAP[i - 1][k])
{
MAP[i][k] *= 2
gre += MAP[i][k]
if (MAP[i][k] == 2048)
return 0
for (t = i - 1 t > 0 t--)
{
MAP[t][k] = MAP[t - 1][k]
MAP[t - 1][k] = 0
tf = 1
}
}
}
}
if (tf)
add(2)
return 1
}
int movlif(void)
{
int i,k,t
for (i = 0 i < 4 i++)
{
int n = 4
while (n--)
for (k = 0 k < 3 k++)
{
if(MAP[i][k] == 0)
for (t = k t < 3 t++)
{
MAP[i][t] = MAP[i][t + 1]
MAP[i][t + 1] = 0
}
}
for (k = 0k < 3k++)
{
if (MAP[i][k] == MAP[i][k + 1])
{
MAP[i][k] *= 2
gre += MAP[i][k]
if (MAP[i][k] == 2048)
return 0
for (t = k + 1 t < 3 t++)
{
MAP[i][t] = MAP[i][t + 1]
MAP[i][t + 1] = 0
}
}
}
}
add(3)
return 1
}
int movri(void)
{
int i,k,t
for (i = 0 i < 4 i++)
{
int n = 4
while (n--)
for (k = 3 k > 0 k--)
{
if(MAP[i][k] == 0)
for (t = k t > 0 t--)
{
MAP[i][t] = MAP[i][t - 1]
MAP[i][t - 1] = 0
}
}
for (k = 3k > 0k--)
{
if (MAP[i][k] == MAP[i][k - 1])
{
MAP[i][k] *= 2
gre += MAP[i][k]
if (MAP[i][k] == 2048)
return 0
for (t = k - 1 t > 0 t--)
{
MAP[i][t] = MAP[i][t - 1]
MAP[i][t - 1] = 0
}
}
}
}
add(4)
return 1
}
int mov(void)
{
char key
int tf = 1
fflush(stdin)
key = getch()
if (key == 72)
tf = movup()
else if (key == 80)
tf = movdow()
else if (key == 75)
tf = movlif()
else if (key == 77)
tf = movri()
if (!tf)
{
system("CLS")
printf ("恭喜达到2048！\n")
}
return tf
}
int pd (void)
{
int i,k
for (i = 0 i < 4 i++)
{
for (k = 1 k < 4 k++)
if (MAP[i][k - 1] == MAP[i][k])
return 0
}
for (i = 0 i < 4 i++)
{
for (k = 1 k < 4 k++)
if (MAP[k - 1][i] == MAP[k][i])
return 0
}
system("CLS")
printf ("游戏结束！\n")
return 1
}
int pri (void)
{
printf ("得分：%d\n",gre)
printf ("\t┏━━┳━━┳━━┳━━┓\n")
printf ("\t┃%4d┃%4d┃%4d┃%4d┃\n",MAP[0][0],MAP[0][1],MAP[0][2],MAP[0][3])
printf ("\t┣━━╋━━╋━━╋━━┫\n")
printf ("\t┃%4d┃%4d┃%4d┃%4d┃\n",MAP[1][0],MAP[1][1],MAP[1][2],MAP[1][3])
printf ("\t┣━━╋━━╋━━╋━━┫\n")
printf ("\t┃%4d┃%4d┃%4d┃%4d┃\n",MAP[2][0],MAP[2][1],MAP[2][2],MAP[2][3])
printf ("\t┣━━╋━━╋━━╋━━┫\n")
printf ("\t┃%4d┃%4d┃%4d┃%4d┃\n",MAP[3][0],MAP[3][1],MAP[3][2],MAP[3][3])
printf ("\t┗━━┻━━┻━━┻━━┛\n")
}
int main()
{
int i
char s[100]
system("COLOR 5F")
printf ("\n\t【2048】控制台版\n\n")
printf ("游戏规则（如同名手游）：\n")
printf ("\t开始方格内会出现2或者4等这两个小数字，\n")
printf ("\t玩家只需要上下左右（方向键控制）其中一个方向来移动出现的数字，\n")
printf ("\t所有的数字就会向滑动的方向靠拢，\n")
printf ("\t而滑出的空白方块就会随机出现一个数字，\n")
printf ("\t相同的数字相撞时会叠加靠拢，\n")
printf ("\t然后一直这样，不断的叠加最终拼凑出2048这个数字就算成功。\n")
printf ("\n\n!输入任意非零字符开始游戏!\n（建议将控制台设置为大字体）\n")
while (scanf ("%s",s),strcmp(s,"0"))
{
memset (MAP,0,sizeof (MAP))
gre = 0
system("CLS")
add(0)
pri()
while (mov())
{
fflush(stdin)
system("CLS")
pri()
if (pd())
break
}
printf ("按任继续游戏！输入0退出程序！\n")
}
return 0
}
#include<stdio.h>#include<string.h>
int main()
{
int cpp(int *)
int input(int *, int )
int n,a[4][4]
scanf("%d",n)
for(int i=0i<ni++)
{
input(a, n)
cpp((intput))
}
return 0
}
int input(int *a, int n)
{
int a[4][4],n
for(int i=0i<4i++)
for(int j=0j<敏返桐4j++)
scanf("%d",&a[i][j])
}
int cpp(int *p)
{
for(int i=0i<4i++)
{
for(int j=0j<4j++)
{if(a[i][j]==a[i+1][j]||a[i][j]==a[i][j+1]) {goto motobreak}
else goto errorbreak} }
moto:{printf("世指Yes.\n"桥坦)return 0}
error:{printf("No.\n")return 0}
}
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