int main()
{
int i,j,k=0,k1,n,need[100]= {0},a[100]= {0},flag=0
scanf("%d",&n)
for(i=0 i<n i++)
scanf("%d",&need[i])
for(k=0 k<n)
{
i=0 k1=0
for(i=0 i<100 i+=5)
{
for(j=0 j<5 j++)
if(a[i+j]==0) flag++
if(flag>=need[k])
{
for(flag=need[k] flag>0)
{
for(j=0 j<5 j++)
汪团 {
if(a[i+j]==0)
{
握陆 a[i+j]=1
flag--
printf("%d ",i+j+1)
if(flag==0)
{
k++
k1=1
break
}
}
}
}
printf("\n"困皮橘)
}
else flag=0
if(k1)break
}
}
return 0
}
#include <stdio.h>int main (void)
{
int n
float f,c,y,i
char g
printf ("请输入F舱、C舱和Y舱的公者穗布价\n")
scanf ("%f %f %f",&f,&c,&y)
getchar ()
scanf ("%c %d",&g,&n)
switch (g)
{
case 'B':i=y*0.9*nbreak
case 'H'兄稿:i=y*0.85*nbreak
case 'K':i=y*0.8*nbreak
case 'L':i=y*0.75*nbreak
case 'M':i=y*0.7*nbreak
case 'N':i=y*0.65*nbreak
case 'Q':i=y*0.6*nbreak
case 'T':i=y*0.55*nbreak
case 'X':i=y*0.5*nbreak
}
printf ("%.2f\n",i)
}
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