C语言扫雷游戏源代码

"扫雷"小游戏C代码

#include<stdio.h>

#include<math.h>

#include<time.h>

#include<stdlib.h>

main( )

{char a[102][102],b[102][102],c[102][102],w

int i,j /*循环变量*/

int x,y,z[999] /*雷的位置*/

int t,s /*标记*/

int m,n,lei /*计数*/

int u,v /*输入*/

int hang,lie,ge,mo /*自定义变量*/

srand((int)time(NULL)) /*启动随机数发生器*/

leb1:  /*选择模式*/

printf("\n   请选择模式：\n   1.标准  2.自定义\n")

scanf("%d",&mo)

if(mo==2)  /*若选择自定义模式，要输入三个参数*/

{do

{t=0printf("请输入\n行数 列数 雷的个数\n")

scanf("%d%d%d",&hang,&lie,&ge)

if(hang<2){printf("行数太少\n")t=1}

if(hang>100){printf("行数太多\n")t=1}

if(lie<2){printf("列数太少\n")t=1}

if(lie>100){printf("列数太多\n")t=1}

if(ge<1){printf("至少要有一个雷\n")t=1}

if(ge>=(hang*lie)){printf("雷太多了\n"哪清)t=1}

}while(t==1)

}

else{hang=10,lie=10,ge=10}  /*否则就是选择了标准模式(默认参数)*/

for(i=1i<=gei=i+1)  /*确定雷的位置李拍前*/

{do

{t=0z[i]=rand( )%(hang*lie)

for(j=1j<ij=j+1){if(z[i]==z[j]) t=1}

}while(t==1)

}

for(i=0i<=hang+1i=i+1)  /*初始化a,b,c*/

{for(j=0j<=lie+1j=j+1) {a[i][j]='1'b[i][j]='1'c[i][j]='0'} }

for(i=1i<=hangi=i+1)

{for(j=1j<=liej=j+1) {a[i][j]='+'} }

for(i=1i<=gei=i+1)  /*把雷放入c*/

{x=z[i]/lie+1y=z[i]%lie+1c[x][y]='#'}

for(i=1i<=hangi=i+1)  /*计算b中数字*/

{for(j=1j<=liej=j+1)

{m=48

if(c[i-1][j-1]=='#')m=m+1if(c[i][j-1]=='#')m=m+1

if(c[i-1][j]=='#')m=m+1 if(c[i+1][j+1]=='#')m=m+1

if(c[i][j+1]=='#')m=m+1 if(c[i+1][j]=='#')m=m+1

if(c[i+1][j-1]=='#')m=m+1if(c[i-1][j+1]=='#')m=m+1

b[i][j]=m

}

}

for(i=1i<=gei=i+1)  /*把雷放入b中*/

{x=z[i]/lie+1y=z[i]%lie+1b[x][y]='#'}

lei=ge /*以下是游戏设计*/

do

{leb2:  /*输出*/

system("cls")printf("\n\n\n\n")

printf("    贺迅")

for(i=1i<=liei=i+1)

{w=(i-1)/10+48printf("%c",w)

w=(i-1)%10+48printf("%c  ",w)

}

printf("\n   |")

for(i=1i<=liei=i+1){printf("---|")}

printf("\n")

for(i=1i<=hangi=i+1)

{w=(i-1)/10+48printf("%c",w)

w=(i-1)%10+48printf("%c |",w)

for(j=1j<=liej=j+1)

{if(a[i][j]=='0')printf("   |")

else printf(" %c |",a[i][j])

}

if(i==2)printf(" 剩余雷个数")

if(i==3)printf(" %d",lei)

printf("\n   |")

for(j=1j<=liej=j+1){printf("---|")}

printf("\n")

}

scanf("%d%c%d",&u,&w,&v) /*输入*/

u=u+1,v=v+1

if(w!='#'&&a[u][v]=='@')

goto leb2

if(w=='#')

{if(a[u][v]=='+'){a[u][v]='@'lei=lei-1}

else if(a[u][v]=='@'){a[u][v]='?'lei=lei+1}

else if(a[u][v]=='?'){a[u][v]='+'}

goto leb2

}

a[u][v]=b[u][v]

leb3:  /*打开0区*/

t=0

if(a[u][v]=='0')

{for(i=1i<=hangi=i+1)

{for(j=1j<=liej=j+1)

{s=0

if(a[i-1][j-1]=='0')s=1if(a[i-1][j+1]=='0')s=1

if(a[i-1][j]=='0')s=1 if(a[i+1][j-1]=='0')s=1

if(a[i+1][j+1]=='0')s=1if(a[i+1][j]=='0')s=1

if(a[i][j-1]=='0')s=1 if(a[i][j+1]=='0')s=1

if(s==1)a[i][j]=b[i][j]

}

}

for(i=1i<=hangi=i+1)

{for(j=liej>=1j=j-1)

{s=0

if(a[i-1][j-1]=='0')s=1if(a[i-1][j+1]=='0')s=1

if(a[i-1][j]=='0')s=1 if(a[i+1][j-1]=='0')s=1

if(a[i+1][j+1]=='0')s=1if(a[i+1][j]=='0')s=1

if(a[i][j-1]=='0')s=1   if(a[i][j+1]=='0')s=1

if(s==1)a[i][j]=b[i][j]

}

}

for(i=hangi>=1i=i-1)

{for(j=1j<=liej=j+1)

{s=0

if(a[i-1][j-1]=='0')s=1if(a[i-1][j+1]=='0')s=1

if(a[i-1][j]=='0')s=1 if(a[i+1][j-1]=='0')s=1

if(a[i+1][j+1]=='0')s=1if(a[i+1][j]=='0')s=1

if(a[i][j-1]=='0')s=1 if(a[i][j+1]=='0')s=1

if(s==1)a[i][j]=b[i][j]

}

}

for(i=hangi>=1i=i-1)

{for(j=liej>=1j=j-1)

{s=0

if(a[i-1][j-1]=='0')s=1if(a[i-1][j+1]=='0')s=1

if(a[i-1][j]=='0')s=1 if(a[i+1][j-1]=='0')s=1

if(a[i+1][j+1]=='0')s=1if(a[i+1][j]=='0')s=1

if(a[i][j-1]=='0')s=1  if(a[i][j+1]=='0')s=1

if(s==1)a[i][j]=b[i][j]

}

}

for(i=1i<=hangi=i+1)  /*检测0区*/

{for(j=1j<=liej=j+1)

{if(a[i][j]=='0')

{if(a[i-1][j-1]=='+'||a[i-1][j-1]=='@'||a[i-1][j-1]=='?')t=1

if(a[i-1][j+1]=='+'||a[i-1][j+1]=='@'||a[i-1][j+1]=='?')t=1

if(a[i+1][j-1]=='+'||a[i+1][j-1]=='@'||a[i+1][j-1]=='?')t=1

if(a[i+1][j+1]=='+'||a[i+1][j+1]=='@'||a[i+1][j+1]=='?')t=1

if(a[i+1][j]=='+'||a[i+1][j]=='@'||a[i+1][j]=='?')t=1

if(a[i][j+1]=='+'||a[i][j+1]=='@'||a[i][j+1]=='?')t=1

if(a[i][j-1]=='+'||a[i][j-1]=='@'||a[i][j-1]=='?')t=1

if(a[i-1][j]=='+'||a[i-1][j]=='@'||a[i-1][j]=='?')t=1

}

}

}

if(t==1)goto leb3

}

n=0 /*检查结束*/

for(i=1i<=hangi=i+1)

{for(j=1j<=liej=j+1)

{if(a[i][j]!='+'&&a[i][j]!='@'&&a[i][j]!='?')n=n+1}

}

}

while(a[u][v]!='#'&&n!=(hang*lie-ge))

for(i=1i<=gei=i+1)  /*游戏结束*/

{x=z[i]/lie+1y=z[i]%lie+1a[x][y]='#'}

printf("    ")

for(i=1i<=liei=i+1)

{w=(i-1)/10+48printf("%c",w)

w=(i-1)%10+48printf("%c  ",w)

}

printf("\n   |")

for(i=1i<=liei=i+1){printf("---|")}

printf("\n")

for(i=1i<=hangi=i+1)

{w=(i-1)/10+48printf("%c",w)

w=(i-1)%10+48printf("%c |",w)

for(j=1j<=liej=j+1)

{if(a[i][j]=='0')printf(" |")

else  printf(" %c |",a[i][j])

}

if(i==2)printf(" 剩余雷个数")

if(i==3)printf(" %d",lei)printf("\n   |")

for(j=1j<=liej=j+1) {printf("---|")}

printf("\n")

}

if(n==(hang*lie-ge)) printf("你成功了!\n")

else printf("    游戏结束!\n")

printf("    重玩请输入1\n")

t=0

scanf("%d",&t)

if(t==1)goto leb1

}

/*注：在DEV c++上运行通过。行号和列号都从0开始，比如要确定第0行第9列不是“雷”，就在0和9中间加入一个字母，可以输入【0a9】三个字符再按回车键。3行7列不是雷，则输入【3a7】回车；第8行第5列是雷，就输入【8#5】回车，9行0列是雷则输入【9#0】并回车*/

给你一个完整的扫雷源码

#include <知烂销conio.h>

#include <graphics.h>

#include <stdio.h>

#include <stdlib.h>

#include <time.h>

#include <ctype.h>

#include "搭游mouse.c"

#define YES 1

#define NO 0

#define XPX 15 /* X pixels by square */

#define YPX 15 /* Y pixels by square */

#define DEFCX 30 /* Default number of squares */

#define DEFCY 28

#define MINE 255-'0' /* So that when it prints, it prints char 0xff */

#define STSQUARE struct stsquare

STSQUARE {

unsigned char value/* Number of mines in the surround squares */

unsigned char sqopen/* Square is open */

unsigned char sqpress/* Square is pressed */

unsigned char sqmark/* Square is marked */

} *psquare

#define value(x,y) (psquare+(x)*ncy+(y))->value

#define sqopen(x,y) (psquare+(x)*ncy+(y))->sqopen

#define sqpress(x,y) (psquare+(x)*ncy+(y))->sqpress

#define sqmark(x,y) (psquare+(x)*ncy+(y))->sqmark

int XST, /* Offset of first pixel X */

YST,

ncx, /* Number of squares in X */

ncy,

cmines, /* Mines discovered */

initmines, /* Number of initial mines */历扮

sqclosed, /* Squares still closed */

maxy/* Max. number of y pixels of the screen */

void Graph_init(void)

void Read_param(int argc, char *argv[])

void Set_mines(int nminas)

void Set_square(int x, int y, int status)

void Mouse_set(void)

void Draw_squares(void)

int Do_all(void)

void Blow_up(void)

void Open_square(int x, int y)

int Open_near_squares(int x, int y)

/************************************************************************/

void main(int argc, char *argv[])

{

if (!mouse_reset()) {

cputs(" ERROR: I can't find a mouse driver\r\n")

exit(2)

}

Graph_init()

Read_param(argc, argv)

Mouse_set()

do {

randomize()

cleardevice()

Set_mines(cmines=initmines)

mouse_enable()

Draw_squares()

}

while (Do_all() != '\x1b')

closegraph()

}

/*************************************************************************

* *

* F U N C T I O N S *

* *

*************************************************************************/

/*----------------------------------------------------------------------*/

void Graph_init(void)

{

int graphdriver=DETECT, graphmode, errorcode

if(errorcode <0) {

cprintf("\n\rGraphics System Error: %s\n",grapherrormsg(errorcode))

exit(98)

}

initgraph(&graphdriver, &graphmode, "")

errorcode=graphresult()

if(errorcode!=grOk) {

printf(" Graphics System Error: %s\n",grapherrormsg(errorcode))

exit(98)

}

maxy=getmaxy()

} /* Graph_init */

/*----------------------------------------------------------------------*/

void Read_param(int argc, char *argv[])

{

int x, y, m

x=y=m=0

if (argc!=1) {

if (!isdigit(*argv[1])) {

closegraph()

cprintf("Usage is: %s [x] [y] [m]\r\n\n"

"Where x is the horizontal size\r\n"

" y is the vertical size\r\n"

" m is the number of mines\r\n\n"

" Left mouse button: Open the square\r\n"

"Right mouse button: Mark the square\r\n"

" -The first time puts a 'mine' mark\r\n"

" -The second time puts a 'possible "

"mine' mark\r\n"

" -The third time unmarks the square\r\n"

"Left+Right buttons: Open the surrounded squares only if "

"the count of mines\r\n"

" is equal to the number in the square",argv[0])

exit (1)

}

switch (argc) {

case 4: m=atoi(argv[3])

case 3: y=atoi(argv[2])

case 2: x=atoi(argv[1])

}

}

XST=100

ncx=DEFCX

if (maxy==479) {

YST=30

ncy=DEFCY

}

else {

YST=25

ncy=20

}

if (x>0 &&x<ncx)

ncx=x

if (y>0 &&y<ncy) {

YST+=((ncy-y)*YPX)>>1

ncy=y

}

initmines= m ? m : ncx*ncy*4/25/* There are about 16% of mines */

if (((void near*)psquare=calloc(ncx*ncy, sizeof(STSQUARE)))==NULL) {

closegraph()

cputs("ERROR: Not enought memory")

exit(3)

}

} /* Read_param */

/*----------------------------------------------------------------------*/

void Set_mines(int nminas)

{

int mine[N*N],i,c

for(c=0c<10c++)

{

    i=rand()%(N*N)

    if(mine[i]==0) 雹卖mine[i]=1

 清肆耐   答春else c--

}

---