获取作业DSL处理的脚本目录的绝对路径

Wiki中的文档有些误导。这是有效的解决方案。

job_name = "my-pipeline-job"println "script: ${ __FILE__}"println("script directory: ${new File(__FILE__).parent}")job_path = "${new File(__FILE__).parent}"jenkinsfile = job_path + "/Jenkinsfile"pipelineJob(job_name){ description("Jenkins pipeline job") parameters{   stringParam("MyTestParam", "", "a sample parameter") } definition {   cps {      sandbox()      script(readFileFromWorkspace(jenkinsfile))   } }}