照片图像到草图算法

好的，所以我使用马克告诉我的不同技术找到了自己的答案。我使用以下伪代码：

*s = Read-File-Into-Image("/path/to/image")*g = Convert-To-Gray-Scale(s)*i = Invert-Colors(g)*b = Apply-Gaussian-Blur(i)*result = Color-Dodge-Blend-Merge(b,g)

前四种方法很容易在Internet上找到，但是在最后一种方法中，我找不到很多信息，甚至没有源代码。因此，我搜索了PS是如何做到的，并在c
++中找到了以下公式：

((uint8)((B == 255) ? B:min(255, ((A << 8 ) / (255 - B)))))

然后我使用以下代码将其转换为Java：

private int colordodge(int in1, int in2) {    float image = (float)in2;    float mask = (float)in1;    return ((int) ((image == 255) ? image:Math.min(255, (((long)mask << 8 ) / (255 - image)))));}public Bitmap ColorDodgeBlend(Bitmap source, Bitmap layer) {    Bitmap base = source.copy(Config.ARGB_8888, true);    Bitmap blend = layer.copy(Config.ARGB_8888, false);    IntBuffer buffbase = IntBuffer.allocate(base.getWidth() * base.getHeight());    base.copyPixelsToBuffer(buffbase);    buffbase.rewind();    IntBuffer buffBlend = IntBuffer.allocate(blend.getWidth() * blend.getHeight());    blend.copyPixelsToBuffer(buffBlend);    buffBlend.rewind();    IntBuffer buffOut = IntBuffer.allocate(base.getWidth() * base.getHeight());    buffOut.rewind();    while (buffOut.position() < buffOut.limit()) {        int filterInt = buffBlend.get();        int srcInt = buffbase.get();        int redValueFilter = Color.red(filterInt);        int greenValueFilter = Color.green(filterInt);        int bluevalueFilter = Color.blue(filterInt);        int redValueSrc = Color.red(srcInt);        int greenValueSrc = Color.green(srcInt);        int bluevalueSrc = Color.blue(srcInt);        int redValueFinal = colordodge(redValueFilter, redValueSrc);        int greenValueFinal = colordodge(greenValueFilter, greenValueSrc);        int bluevalueFinal = colordodge(bluevalueFilter, bluevalueSrc);        int pixel = Color.argb(255, redValueFinal, greenValueFinal, bluevalueFinal);        buffOut.put(pixel);    }    buffOut.rewind();    base.copyPixelsFromBuffer(buffOut);    blend.recycle();    return base;}

如果可以改进代码，请在下面发布新的答案或评论。谢谢！