根据javascript中的键值合并两个json对象

根据javascript中的键值合并两个json对象

如果

obj

ID中不存在ID，您忘了推入第一个循环；如果ID中不存在该对象的一个​​或多个ID，您忘了

c

循环遍历。

c``g

var g = [        { id: 36, name: 'AAA', goal: 'yes' },        { id: 40, name: 'BBB', goal: 'yes' },        { id: 57, name: 'CCC', goal: 'yes' },        { id: 4, name: 'DDD', goal: 'yes' },        { id: 39, name: 'EEE', goal: 'yes' },        { id: 37, name: 'FFF', goal: 'yes' },        { id: 59, name: 'GGG', goal: 'yes' },        { id: 50, name: 'III', goal: 'yes' },        { id: 43, name: 'HHH', goal: 'yes' },        { id: 35, name: 'JJJ', goal: 'yes' }    ],    c = [        { id: 36, name: 'AAA', circle: 'yes' },        { id: 40, name: 'BBB', circle: 'yes' },        { id: 57, name: 'CCC', circle: 'yes' },        { id: 42, name: 'ZZZ', circle: 'yes' },        { id: 4, name: 'DDD', circle: 'yes' },        { id: 39, name: 'EEE', circle: 'yes' },        { id: 37, name: 'FFF', circle: 'yes' },        { id: 59, name: 'GGG', circle: 'yes' },        { id: 43, name: 'HHH', circle: 'yes' },        { id: 35, name: 'JJJ', circle: 'yes' },        { id: 100, name: 'JJJ', circle: 'yes' }    ],    arrayList = [], obj_c_processed = [];for (var i in g) {    var obj = {id: g[i].id, name: g[i].name, goal: g[i].goal};    for (var j in c) {        if (g[i].id == c[j].id) { obj.circle = c[j].circle; obj_c_processed[c[j].id] = true;        }    }    obj.circle = obj.circle || 'no';    arrayList.push(obj);}for (var j in c){    if (typeof obj_c_processed[c[j].id] == 'undefined') {        arrayList.push({id: c[j].id, name: c[j].name, goal: 'no', circle: c[j].circle});    }}console.log(arrayList);