Python-家庭作业-将任何基础转换为任何基础

Python-家庭作业-将任何基础转换为任何基础

这应该是您问题的答案的上半部分。您能弄清楚如何转换为基数吗？

# Create a symbol-to-value table.SY2VA = {'0': 0,         '1': 1,         '2': 2,         '3': 3,         '4': 4,         '5': 5,         '6': 6,         '7': 7,         '8': 8,         '9': 9,         'A': 10,         'B': 11,         'C': 12,         'D': 13,         'E': 14,         'F': 15,         'G': 16,         'H': 17,         'I': 18,         'J': 19,         'K': 20,         'L': 21,         'M': 22,         'N': 23,         'O': 24,         'P': 25,         'Q': 26,         'R': 27,         'S': 28,         'T': 29,         'U': 30,         'V': 31,         'W': 32,         'X': 33,         'Y': 34,         'Z': 35,         'a': 36,         'b': 37,         'c': 38,         'd': 39,         'e': 40,         'f': 41,         'g': 42,         'h': 43,         'i': 44,         'j': 45,         'k': 46,         'l': 47,         'm': 48,         'n': 49,         'o': 50,         'p': 51,         'q': 52,         'r': 53,         's': 54,         't': 55,         'u': 56,         'v': 57,         'w': 58,         'x': 59,         'y': 60,         'z': 61,         '!': 62,         '"': 63,         '#': 64,         '$': 65,         '%': 66,         '&': 67,         "'": 68,         '(': 69,         ')': 70,         '*': 71,         '+': 72,         ',': 73,         '-': 74,         '.': 75,         '/': 76,         ':': 77,         ';': 78,         '<': 79,         '=': 80,         '>': 81,         '?': 82,         '@': 83,         '[': 84,         '\': 85,         ']': 86,         '^': 87,         '_': 88,         '`': 89,         '{': 90,         '|': 91,         '}': 92,         '~': 93}# Take a string and base to convert to.# Allocate space to store your number.# For each character in your string:#     Ensure character is in your table.#     Find the value of your character.#     Ensure value is within your base.#     Self-multiply your number with the base.#     Self-add your number with the digit's value.# Return the number.def str2int(string, base):    integer = 0    for character in string:        assert character in SY2VA, 'Found unknown character!'        value = SY2VA[character]        assert value < base, 'Found digit outside base!'        integer *= base        integer += value    return integer

这是解决方案的后半部分。通过使用这两个函数，转换基数非常容易。

# Create a value-to-symbol table.VA2SY = dict(map(reversed, SY2VA.items()))# Take a integer and base to convert to.# Create an array to store the digits in.# While the integer is not zero:#     Divide the integer by the base to:#         (1) Find the "last" digit in your number (value).#         (2) Store remaining number not "chopped" (integer).#     Save the digit in your storage array.# Return your joined digits after putting them in the right order.def int2str(integer, base):    array = []    while integer:        integer, value = divmod(integer, base)        array.append(VA2SY[value])    return ''.join(reversed(array))

将所有内容放在一起后，您应该结束下面的程序。请花点时间弄清楚！

innitvar = raw_input("Please enter a number: ")basevar = int(raw_input("Please enter the base that your number is in: "))convertvar = int(raw_input("Please enter the base that you would like to convert to: "))# Create a symbol-to-value table.SY2VA = {'0': 0,         '1': 1,         '2': 2,         '3': 3,         '4': 4,         '5': 5,         '6': 6,         '7': 7,         '8': 8,         '9': 9,         'A': 10,         'B': 11,         'C': 12,         'D': 13,         'E': 14,         'F': 15,         'G': 16,         'H': 17,         'I': 18,         'J': 19,         'K': 20,         'L': 21,         'M': 22,         'N': 23,         'O': 24,         'P': 25,         'Q': 26,         'R': 27,         'S': 28,         'T': 29,         'U': 30,         'V': 31,         'W': 32,         'X': 33,         'Y': 34,         'Z': 35,         'a': 36,         'b': 37,         'c': 38,         'd': 39,         'e': 40,         'f': 41,         'g': 42,         'h': 43,         'i': 44,         'j': 45,         'k': 46,         'l': 47,         'm': 48,         'n': 49,         'o': 50,         'p': 51,         'q': 52,         'r': 53,         's': 54,         't': 55,         'u': 56,         'v': 57,         'w': 58,         'x': 59,         'y': 60,         'z': 61,         '!': 62,         '"': 63,         '#': 64,         '$': 65,         '%': 66,         '&': 67,         "'": 68,         '(': 69,         ')': 70,         '*': 71,         '+': 72,         ',': 73,         '-': 74,         '.': 75,         '/': 76,         ':': 77,         ';': 78,         '<': 79,         '=': 80,         '>': 81,         '?': 82,         '@': 83,         '[': 84,         '\': 85,         ']': 86,         '^': 87,         '_': 88,         '`': 89,         '{': 90,         '|': 91,         '}': 92,         '~': 93}# Take a string and base to convert to.# Allocate space to store your number.# For each character in your string:#     Ensure character is in your table.#     Find the value of your character.#     Ensure value is within your base.#     Self-multiply your number with the base.#     Self-add your number with the digit's value.# Return the number.integer = 0for character in innitvar:    assert character in SY2VA, 'Found unknown character!'    value = SY2VA[character]    assert value < basevar, 'Found digit outside base!'    integer *= basevar    integer += value# Create a value-to-symbol table.VA2SY = dict(map(reversed, SY2VA.items()))# Take a integer and base to convert to.# Create an array to store the digits in.# While the integer is not zero:#     Divide the integer by the base to:#         (1) Find the "last" digit in your number (value).#         (2) Store remaining number not "chopped" (integer).#     Save the digit in your storage array.# Return your joined digits after putting them in the right order.array = []while integer:    integer, value = divmod(integer, convertvar)    array.append(VA2SY[value])answer = ''.join(reversed(array))# Display the results of the calculations.print answer