如何找到退出代码或在Python中调用atexit回调时的原因？

如何找到退出代码或在Python中调用atexit回调时的原因？

您可以使用

sys.excepthook

和通过猴子补丁来解决此问题

sys.exit()

：

import atexitimport sysclass ExitHooks(object):    def __init__(self):        self.exit_pre = None        self.exception = None    def hook(self):        self._orig_exit = sys.exit        sys.exit = self.exit        sys.excepthook = self.exc_handler    def exit(self, pre=0):        self.exit_pre = pre        self._orig_exit(pre)    def exc_handler(self, exc_type, exc, *args):        self.exception = exchooks = ExitHooks()hooks.hook()def foo():    if hooks.exit_pre is not None:        print("death by sys.exit(%d)" % hooks.exit_pre)    elif hooks.exception is not None:        print("death by exception: %s" % hooks.exception)    else:        print("natural death")atexit.register(foo)# testsys.exit(1)