APT命令行界面一样的是否输入？

APT命令行界面一样的是/否输入？

正如您提到的，最简单的方法是使用

raw_input()

（或仅

input()

对于Python
3
）。没有内置的方法可以做到这一点。从577058号配方中：

import sysdef query_yes_no(question, default="yes"):    """Ask a yes/no question via raw_input() and return their answer.    "question" is a string that is presented to the user.    "default" is the presumed answer if the user just hits <Enter>.        It must be "yes" (the default), "no" or None (meaning        an answer is required of the user).    The "answer" return value is True for "yes" or False for "no".    """    valid = {"yes": True, "y": True, "ye": True,  "no": False, "n": False}    if default is None:        prompt = " [y/n] "    elif default == "yes":        prompt = " [Y/n] "    elif default == "no":        prompt = " [y/N] "    else:        raise ValueError("invalid default answer: '%s'" % default)    while True:        sys.stdout.write(question + prompt)        choice = raw_input().lower()        if default is not None and choice == '': return valid[default]        elif choice in valid: return valid[choice]        else: sys.stdout.write("Please respond with 'yes' or 'no' "       "(or 'y' or 'n').n")

用法示例：

>>> query_yes_no("Is cabbage yummier than cauliflower?")Is cabbage yummier than cauliflower? [Y/n] oopsPlease respond with 'yes' or 'no' (or 'y' or 'n').Is cabbage yummier than cauliflower? [Y/n] [ENTER]>>> True>>> query_yes_no("Is cabbage yummier than cauliflower?", None)Is cabbage yummier than cauliflower? [y/n] [ENTER]Please respond with 'yes' or 'no' (or 'y' or 'n').Is cabbage yummier than cauliflower? [y/n] y>>> True