如何从HTML获取数据以在SQL中进行查询？

如何从HTML获取数据以在SQL中进行查询？

您可以使用AJAX来完成。了解这些：

http://www.w3schools.com/ajax/

http://php.net/manual/zh/mysqli.quickstart.prepared-
statements.php

准备好的语句将使您免受SQL Injection攻击。如果要查询的是来自用户的输入，请练习专门使用它。

的HTML

<a href="#myModal" data-toggle="modal" id="78"  data-target="#edit-modal">  <button type="button">    <i ></i>  </button></a><div id="edit-modal">  <div ></div></div>

PHP（content.php）使用程序化mysql

<?php          $er = $_POST['id'];   $str = "SELECt * FROM examquestion WHERe EQ_ID = '$er' ";   $Recordset7 = mysql_query($str) or die(mysql_error());   $row_Recordset7 = mysql_fetch_assoc($Recordset7);   echo $row_Recordset7['EQ_ID'];  ?>

PHP使用OOP mysqli（准备好的语句）

$mysqli = new mysqli("localhost", "user", "password", "database");$query = "SELECt content FROM examquestion WHERe EQ_ID = ?";if ( $stmt = $mysqli->prepare($query) ){    $stmt->bind_param("s", $er);    if ( $stmt->execute() )    {       $stmt->bind_result($content);       while ($stmt->fetch()) {          echo $content;       }    }    $stmt->close();}

JS

<script>        $('a.get-content').click(function() { var contentId = $(this).attr('id'); var modalId = $(this).attr('data-target'); $.ajax({     url: "content.php",     type: "POST",     data: {id: contentId},     dataType: "html",     success:function(data){         $(modalId).find('.edit-content').eq(0).html(data);      } });        });</script>