python字典值排序

小命令的简单解决方案是

dict1 = {"a":0.6, "b":0.3, "c":0.9, "d":1.2, "e":0.2}dict2 = {"a":1.4, "b":7.7, "c":9.0, "d":2.5, "e":2.0}k1 = sorted(dict1, key=dict1.get)k2 = sorted(dict2, key=dict2.get)diffs = dict((k, k2.index(k) - k1.index(k)) for k in dict1)

适用于较大字典的更有效，更易理解的版本：

ranks1 = dict(map(reversed, enumerate(sorted(dict1, key=dict1.get))))ranks2 = dict(map(reversed, enumerate(sorted(dict2, key=dict2.get))))diffs = dict((k, ranks2[k] - ranks1[k]) for k in dict1)