不论文件扩展名如何，均使用相同名称获取文件

不论文件扩展名如何，均使用相同名称获取文件

您可以使用该

fnmatch.filter()

函数来识别感兴趣的文件名：

import os, fnmatchdef get_all_files(path, pattern):    datafiles = []    for root,dirs,files in os.walk(path):        for file in fnmatch.filter(files, pattern): pathname = os.path.join(root, file) filesize = os.stat(pathname).st_size datafiles.append([file, pathname, filesize])    return datafilesprint get_all_files('.', 'something.*') # all files named 'something'

但是请注意，通过增加几行代码，也可以使某些通用类支持所有

os.walk()

的关键字参数：

import os, fnmatchdef glob_walk(top, pattern, **kwargs):    """ Wrapper for os.walk() that filters the files returned        with a pattern composed of Unix shell-style wildcards        as documented in the fnmatch module.    """    for root, dirs, files in os.walk(top, **kwargs):        yield root, dirs, fnmatch.filter(files, pattern)# sample usagedef get_all_files(path, pattern):    for root, dirs, files in glob_walk(path, pattern):        for file in files: pathname = os.path.join(root, file) filesize = os.stat(pathname).st_size yield file, pathname, filesizeprint list(get_all_files('.', 'something.*')) # all files named 'something'

请注意，此版本中的新

glob_walk()

函数（与wll一样

get_all_files()

）是生成器，就像

os.walk()

。