Python相当于Ruby的define_method吗？

Python相当于Ruby的define_method吗？

函数是Python中的一流对象，可以分配给类或实例的属性。与Wikipedia示例相同的方法之一是：

colours = {"black": "000","red": "f00","green": "0f0","yellow": "ff0","blue": "00f","magenta": "f0f","cyan": "0ff","white": "fff"}class MyString(str):    passfor name, pre in colours.iteritems():    def _in_colour(self, pre=pre):        return '<span >%s</span>' % (pre, self)    setattr(MyString, "in_" + name, _in_colour)