第一种方法第二种方法
第一种方法ObjectMapper mapper = new ObjectMapper(); // 排除json字符串中实体类没有的字段 objectMapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES,false); String json = "[{"name":"a","age":"345"},{"name":"b","age":"123"}]"; List第二种方法list = mapper.readValue(json, new TypeReference >(){});
JavaType javaType = mapper.getTypeFactory().constructCollectionType(List.class, Persion.class); Listlist2 = mapper.readValue(json, javaType);
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