1、在mysql环境,创建数据库表,
create table test_data1(id int, name VARCHAR(20), day VARCHAR(20))
2、插入测试数据,
insert into test_data1 values(1,'liu',1)
insert into test_data1 values(2,'liu',3)
insert into test_data1 values(3,'wang',1)
insert into test_data1 values(4,'wang',2)
insert into test_data1 values(4,'wang',4)
3、查询表中数据,select * from test_data1;
4、编写目标sql;
select name,
max(case when day=1 then 1 end) d_1,
max(case when day=2 then 2 end) d_2,
max(case when day=3 then 3 end) d_3,
max(case when day=4 then 4 end) d_4
from test_data1 t group by name
如果你的prodid和date是固定的对应关系,每个日期都有proid为1、2、3的三个数数据,那可以这么写
SELECT DATE,IFNULL((SELECT total FROM ProS s0 WHERE s0.DATE = w.DATE AND s0.proid = 1), 0) A,
IFNULL((SELECT total FROM ProS s1 WHERE s1.DATE = w.DATE AND s1.proid = 2), 0) B,
IFNULL((SELECT total FROM ProS s2 WHERE s2.DATE = w.DATE AND s2.proid = 3), 0) C
FROM ProS w
GROUP BY DATE
欢迎分享,转载请注明来源:内存溢出
评论列表(0条)