求教高手,HTML连线题怎样制作?

求教高手,HTML连线题怎样制作?,第1张

用canvas实现,可以实现。划线的位置 你自己调调。还有对象创建

canvas = $('#myCanvas')[0]

ctx = canvas.getContext('2d')

// 画出左边到右边的连接

linkWith: function(ctxx, leftIndex, rightIndex) {

console.log("link "+leftIndex+" with "+rightIndex)

ctxx.beginPath()

ctxx.moveTo(0.5,(2*leftIndex-1)*cellHeight + 0.5)

ctxx.lineWidth=1

ctxx.lineTo(canvasWidth +0.5,(2*rightIndex-1)*cellHeight + 0.5)

ctxx.stroke()

ctxx.closePath()

},

<!doctype html>

<html>

<head>

<meta http-equiv="Pragma" content="no-cache" />

<meta http-equiv="Cache-Control" content="no-cache" />

<meta http-equiv="Expires" content="0" />

<meta http-equiv="Content-Type" content="text/htmlcharset=utf-8" />

<meta name="viewport" content="width=device-width,initial-scale=1.0,user-scalable=no" />

<style type="text/css">

html{

height: 100%

}

html,body,ul,li,canvas{

margin: 0

padding: 0

}

</style>

</head>

<body bgcolor="#000000">

<canvas id="knife"></canvas>

</body>

<script>

var canvas = document.getElementById("knife")

canvas.style.position = "absolute"

canvas.style.top = 0

var w = window.innerWidth

var h = window.innerHeight

canvas.width = w

canvas.height = h

var cxt = canvas.getContext("2d")

cxt.strokeStyle = "#FFF"

var list = []

var G = 0.4 //向心加速度

var SPEED_Y = -1 //向上速度

var centerLine = w/2 //龙卷风中线

function addLine(){

var LEN = 2

for(var i = 0 i <LEN i ++){

list.push({

x:w/2,

y:h/1.3,

g:G,

c:centerLine+2*Math.random(),

sx:(Math.random()-0.5)*4,

sy:SPEED_Y+0.5*(Math.random()-0.5),

len:Math.round(Math.random()*10+5),

list:[{x:w/2,y:h/1.3}]

})

}

}

function step(){

cxt.clearRect(0,0,w,h)

addLine()

var obj

for(var i = 0 i <list.lengthi ++){

obj = list[i]

if(obj.y <h/2.5){//如果超过这个高度,就删除一个点

obj.len --

if(obj.len == 0){

list.splice(i,1)

i --

continue

}

}

obj.x += obj.sx

obj.y += obj.sy

obj.sx += obj.g

obj.g = obj.x >obj.c ? -G : G

obj.list.unshift({x:obj.x,y:obj.y})//记录下质点运动轨迹

obj.list = obj.list.slice(0,obj.len)//仅仅画出其中一段线就好

//画出所有点的连线

cxt.beginPath()

cxt.moveTo(obj.list[0].x,obj.list[0].y)

for(var j = 1 j <obj.list.lengthj ++){

cxt.lineTo(obj.list[j].x,obj.list[j].y)

}

cxt.stroke()

}

requestAnimationFrame(step)

}

requestAnimationFrame(step)

</script>

</html>


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原文地址: http://outofmemory.cn/zaji/6199624.html

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