如何从URL向html传输数据？

首先获取到地址栏中的网址，然后找到参数。

var url = window.location.href

var num = url.indexOf('?')

var str = url.substring(num + 1, url.length)

var arr = str.split('=')

arr[1]就是你需要的参数了。

2 * @author bzwang**/

public class DynInfo2Html {/*** 将信息转化为静态html

* @param sSourceUrl 动态信息访问URL

* @param sDestDir 存储为静态文件的目录

* @param sHtmlFile 生成的静态文件名,可以按信息的唯一ID+.html命名

* @throws IOException*/public static void convert2Html(String sSourceUrl,String sDestDir,String sHtmlFile) throws IOException{int HttpResult

URL url=new URL(sSourceUrl)

URLConnection urlconn=url.openConnection()

urlconn.connect()

HttpURLConnection httpconn=(HttpURLConnection)urlconn

HttpResult=httpconn.getResponseCode()

if(HttpResult!=HttpURLConnection.HTTP_OK) {}else {InputStreamReader isr =

new InputStreamReader(httpconn.getInputStream())

BufferedReader in = new BufferedReader(isr)

String inputLine

if(!sDestDir.endsWith("/"))sDestDir+="/"

FileOutputStream fout = new FileOutputStream(sDestDir+sHtmlFile)

while ((inputLine = in.readLine()) != null) {

fout.write(inputLine.getBytes())}in.close()fout.close()}}