php+mysql怎么删除重复的记录只保留一个最新的记录？

换个思路， 你再新建一个表，表里的字段跟你这个表的字段一样。。

然后 insert into select from 。。。。这里你应该懂了吧，， 就是去重查询之后，然后将结果集插入到指定的表中。。

MySQL查询重复字段,及删除重复记录的方法

数据库中有个大表，需要查找其中的名字有重复的记录id，以便比较。如果仅仅是查找数据库中name不重复的字段，很容易:

SELECT min(`id`),`name` FROM `table` GROUP BY `name`

但是这样并不能得到说有重复字段的id值。（只得到了最小的一个id值）查询哪些字段是重复的也容易:

SELECT `name`,count(`name`) as count FROM `table` GROUP BY `name` HAVING count(`name`) >1 ORDER BY count DESC

但是要一次查询到重复字段的id值，就必须使用子查询了，于是使用下面的语句。

SELECT `id`,`name` FROM `table` WHERE `name` in (

SELECT `name`

FROM `table`

GROUP BY `name` HAVING count(`name`) >1)

但是这条语句在mysql中效率太差，感觉mysql并没有为子查询生成零时表。于是使用先建立零时表:

create table `tmptable` as (

SELECT `name`

FROM `table`

GROUP BY `name` HAVING count(`name`) >1)

然后使用多表连接查询：

SELECT a.`id`, a.`name` FROM `table` a, `tmptable` t WHERE a.`name` = t.`name`

结果这次结果很快就出来了。

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查询及删除重复记录的方法

(一)

1、查找表中多余的重复记录，重复记录是根据单个字段（peopleId）来判断

select * from people

where peopleId in (select peopleId from people group by peopleId having count(peopleId) >1)

2、删除表中多余的重复记录，重复记录是根据单个字段（peopleId）来判断，只留有rowid最小的记录

delete from people

where peopleId in (select peopleId from people group by peopleId having count(peopleId) >1)

and rowid not in (select min(rowid) from people group by peopleId having count(peopleId )>1)

3、查找表中多余的重复记录（多个字段）

select * from vitae a

where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) >1)

4、删除表中多余的重复记录（多个字段），只留有rowid最小的记录

delete from vitae a

where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) >1)

and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

5、查找表中多余的重复记录（多个字段），不包含rowid最小的记录

select * from vitae a

where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) >1)

and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

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